For the reaction between aqueous solutions of acetic acid (CH3COOH) and barium hydroxide, Ba(OH)2, write
1 answer:
Answer:
See explanation.
Explanation:
Hello!
In this case, since we are asked to note down the complete molecular equation, complete ionic equation and the net ionic equation for the reaction between acetic acid (weak acid) and barium hydroxide (strong base), we proceed as shown below:
- Complete molecular equation:
- Complete ionic equation: in this case, since acetic acid is a weak one, it is not ionized, so we do this:
- Net ionic equation: in this case, we cancel out the barium ions as they are the spectators one because they are present at both reactants and products:
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<u>First of all, what is electrolysis?</u>
Electrolysis is the process of breaking down ionic substances using direct current.
<u>Important points about electrolysis </u>
→ Ionic substances contain particles called ions.
→ Electricity is the flow of electrons or ions. For electrolysis to work, the compound must contain ions. The ions must be free to move for electrolysis to occur and it can happen by melting or dissolving an ionic substance in water.
→ Positively charged ions move to the negative electrode. They receive electrons and are <em>reduced</em>. The positive ions move towards the negative electrode because they want to cancel each other out.
→ Negatively charged ions move to the positive electrode. They lose electrons and are <em>oxidised</em>. The substance that is broken down is called the electrolyte <em>(an electrolyte is just a liquid or solution that can conduct electricity)</em> . The negative ions move towards the positive electrode because they want to cancel each other out.
<h3>Cathode = Negative electrode</h3><h3>Anode = Positive electrode</h3>Metal ions form at the cathode and non-metal ions form at the anode
How I remember if an element is <em>oxidised</em> or <em>reduced</em> is by remembering OIL RIG
OIL = Oxidation is Loss (of electrons)
RIG = Reduction is Gain (of electrons)
<h2><em><u>The answer to your question</u></em></h2>1) The first step would be to clean the metal ring and sand it down because when the metal atoms from the electrolyte are deposited onto the ring, they will form a weak bond and they may simply 'fall' off. Also this could affect conductivity and the whole experiment. The more things you do accurately now, the more accurate your result will be.
2) You want to put the solution you are given in to the tank your going to be using.
3) This is basically the main part, you want to set up the circuit, I have attached a diagram at the bottom to show you the circuit. The copper rod will be the anode and the metal ring will be a cathode (ignore the elements).
4) Now turn on the circuit and you will start to see the solution spilt with the the solution now being split some going to the anode and some going the cathode.
5) Then a thin layer should form on the electrode.
Hope this helps :)
<h2><em><u></u></em></h2><em><u></u></em>
Explanation:
elements are based on electrical conductivity
