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Aleonysh [2.5K]
3 years ago
10

(Help would be greatly appreciated) What is the molarity of a solution which contains 22.41 grams of NaCl in 50.0 mL of solution

?
1. 0.488M
2. 7.67mol
3. 7.67M
4. 0.000767M
Chemistry
1 answer:
luda_lava [24]3 years ago
4 0

Answer:

7.67

Explanation:

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Calculate e°cell for a silver-aluminum cell in which the cell reaction is al(s) + 3ag+(aq) → al3+(aq) + 3ag(s) –2.46 v 0.86 v –0
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When E° cell is an electrochemical cell which comprises of two half cells.
 
So,

when we have the balanced equation of this half cell :

Al3+(aq) + 3e- → Al(s)   and E°1 = -1.66 V 

and we have  also this balanced equation of this half cell :

Ag+(aq)  + e- → Ag(s)  and E°2 = 0.8 V 

so, we can get E° in Al(s) + 3Ag (aq) → Al3+(aq) + 3Ag(s)

when E° = E°2 - E°1

∴E° =0.8 - (-1.66)

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M = n / V

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Then insert in the equation the values from the question;  

M = 0.082 mol  /  2.03 L = 0.04 mol/L

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