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tekilochka [14]
3 years ago
15

Heavy snowfall combined withholding blowing snow results in a(n)

Chemistry
2 answers:
sukhopar [10]3 years ago
7 0

Answer:

D

Explanation:

juin [17]3 years ago
3 0

Answer:

D

Explanation:

You might be interested in
Sandra heated a 12.3-g piece of iron to 100oC. She then placed the iron in a calorimeter with a heat capacity of 10.4 J/oC. The
Thepotemich [5.8K]
We first have to find Q calorimeter

Q calorimeter = C (delta T) 

C= heat capacity in J/oC, not small c ( specific heat capacity) 
delta T= change in T (oC) = final T - initial T 

Q calorimeter = 10.4 J/oC (30 oC - 25 oC)
Q calorimeter = 52 J 

Remember, 

Q calorimeter = - Q surrounding
The (-) negative sign stands for heat being released. 

So , 

Q surrounding = - 52 J 

In other words, the iron releases 52 J .

The calorimeter absorbs the entire 52 J and heat rose from 25 - 30 oC. 

Answer: 52 J


8 0
3 years ago
Gawk gawk? smeat muh meat​
quester [9]

Answer:

bruh why?

Explanation:

4 0
2 years ago
Read 2 more answers
A particular sample of air is 2.5% water vapor express the concentration of water vapor in parts per million
Inessa05 [86]

Answer:

                     25000 ppm

Explanation:

<em>Parts Per Million </em>is defined as the number of parts of a solute per one million parts of a solution.

                  ppm  =  (Weight of Solute / Weight of Solution) × 10⁶   ---(1)

Let us suppose that the air (solution) weights 100 grams, then 2.5 % of water vapors will have following mass,

Mass of Vapors g / 100 g × 100  =  2.5

Or,

Mass of Vapors = 2.5 × 100 / 100

Mass of Vapors  =  2.5 g

Hence, mass of water vapors is 2.5 g.

Now, putting mass of water vapors and air in eq. 1,

                  ppm  =  (2.5 / 100) × 10⁶

                 ppm  =  25000

7 0
3 years ago
Can you live without chemical reactions
Oliga [24]

Answer:

no

Explanation:

your body wouldnt be able to repair, move, or do anything for that matter if we didnt consistently have chemical reactions in us.

7 1
3 years ago
Read 2 more answers
What is the molar out of a solution that contains 33.5g of CaCl2 in 600.0mL of water
omeli [17]

Answer:

Here's what I got.

Explanation:

Interestingly enough, I'm not getting

0.0341% w/v

either. Here's why.

Start by calculating the percent composition of chlorine,

Cl

, in calcium chloride, This will help you calculate the mass of chloride anions,

Cl

−

, present in your sample.

To do that, use the molar mass of calcium chloride, the molar mass of elemental chlorine, and the fact that

1

mole of calcium chloride contains

2

moles of chlorine atoms.

2

×

35.453

g mol

−

1

110.98

g mol

−

1

⋅

100

%

=

63.89% Cl

This means that for every

100 g

of calcium chloride, you get

63.89 g

of chlorine.

As you know, the mass of an ion is approximately equal to the mass of the neutral atom, so you can say that for every

100 g

of calcium chloride, you get

63.89 g

of chloride anions,

Cl

−

.

This implies that your sample contains

0.543

g CaCl

2

⋅

63.89 g Cl

−

100

g CaCl

2

=

0.3469 g Cl

−

Now, in order to find the mass by volume percent concentration of chloride anions in the resulting solution, you must determine the mass of chloride anions present in

100 mL

of this solution.

Since you know that

500 mL

of solution contain

0.3469 g

of chloride anions, you can say that

100 mL

of solution will contain

100

mL solution

⋅

0.3469 g Cl

−

500

mL solution

=

0.06938 g Cl

−

Therefore, you can say that the mass by volume percent concentration of chloride anions will be

% m/v = 0.069% Cl

−

−−−−−−−−−−−−−−−−−−−

I'll leave the answer rounded to two sig figs, but keep in mind that you have one significant figure for the volume of the solution.

.

ALTERNATIVE APPROACH

Alternatively, you can start by calculating the number of moles of calcium chloride present in your sample

0.543

g

⋅

1 mole CaCl

2

110.98

g

=

0.004893 moles CaCl

2

To find the molarity of this solution, calculate the number of moles of calcium chloride present in

1 L

=

10

3

mL

of solution by using the fact that you have

0.004893

moles present in

500 mL

of solution.

10

3

mL solution

⋅

0.004893 moles CaCl

2

500

mL solution

=

0.009786 moles CaCl

2

You can thus say your solution has

[

CaCl

2

]

=

0.009786 mol L

−

1

Since every mole of calcium chloride delivers

2

moles of chloride anions to the solution, you can say that you have

[

Cl

−

]

=

2

⋅

0.009786 mol L

−

1

[

Cl

−

]

=

0.01957 mol L

−

This implies that

100 mL

of this solution will contain

100

mL solution

⋅

0.01957 moles Cl

−

10

3

mL solution

=

0.001957 moles Cl

−

Finally, to convert this to grams, use the molar mass of elemental chlorine

0.001957

moles Cl

−

⋅

35.453 g

1

mole Cl

−

=

0.06938 g Cl

−

Once again, you have

% m/v = 0.069% Cl

−

−−−−−−−−−−−−−−−−−−−

In reference to the explanation you provided, you have

0.341 g L

−

1

=

0.0341 g/100 mL

=

0.0341% m/v

because you have

1 L

=

10

3

mL

.

However, this solution does not contain

0.341 g

of chloride anions in

1 L

. Using

[

Cl

−

]

=

0.01957 mol L

−

1

you have

n

=

c

⋅

V

so

n

=

0.01957 mol

⋅

10

−

3

mL

−

1

⋅

500

mL

n

=

0.009785 moles

This is how many moles of chloride anions you have in

500 mL

of solution. Consequently,

100 mL

of solution will contain

100

mL solution

⋅

0.009785 moles Cl

−

500

mL solution

=

0.001957 moles Cl

−

So once again, you have

0.06938 g

of chloride anions in

100 mL

of solution, the equivalent of

0.069% m/v

.

Explanation:

i think this is it

8 0
3 years ago
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