Answer:
(a) 64.6 kg/ms
(b) 4088.61 N
Explanation:
(a)
I = mΔv.................. Equation 1
Where I = impulse acting on the ball, Δv = change in velocity.
But,
Δv = v-u.............. Equation 2
Where v = final velocity, u = initial velocity.
Substitute equation 2 into equation 1
I = m(v-u).................. Equation 3
Assuming: upwards to be positive
Given: m = 1.9 kg, v = 9 m/s, u = -25 m/s (downward)
Substitute into equation 3
I = 1.9[9-(25)]
I = 1.9(9+25)
I = 1.9(34)
I = 64.6 kgm/s.
(b)
F = I/t................... Equation 4
Where F = Average force on the floor from the ball, t = time of contact of the floor with the ball.
Given: I = 64.6 kgm/s, t = 0.0158 s
Substitute into equation 4
F = 64.6/0.0158
F = 4088.61 N
