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3 years ago

What happens when humans change the flow of water?

2 answers:

8 0

Disaster. (like my life) It'll affect the animals and there will be no way to get their food without water.Hope this helped :)

mafiozo [28]3 years ago

7 0

It would affect the water cycle

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Replacing an object attached to a spring with an object having 14 the original mass will change the frequency of oscillation of

Pachacha [2.7K]

Answer:

The frequency changes by a factor of 0.27.

Explanation:

The frequency of an object with mass m attached to a spring is given as

$f$ = $\frac{1}{2\pi } \sqrt{\frac{k}{m} }$

where $f$ is the frequency

k is the spring constant of the spring

m is the mass of the substance on the spring.

If the mass of the system is increased by 14 means the new frequency becomes

$f_{n}$ = $\frac{1}{2\pi } \sqrt{\frac{k}{14m} }$

simplifying, we have

$f_{n}$ = $\frac{1}{2\pi \sqrt{14} } \sqrt{\frac{k}{m} }$

$f_{n}$ = $\frac{1}{3.742*2\pi } \sqrt{\frac{k}{m} }$

if we divide this final frequency by the original frequency, we'll have

==> $\frac{1}{3.742*2\pi } \sqrt{\frac{k}{m} }$ ÷ $\frac{1}{2\pi } \sqrt{\frac{k}{m} }$

==> $\frac{1}{3.742*2\pi } \sqrt{\frac{k}{m} }$ x $2\pi \sqrt{\frac{m}{k} }$

==> 1/3.742 = 0.27

7 0

3 years ago

What are some superheroes that resemble neurotransmitter functions. Dopamine: Acetylcholine: Endorphins: GABA: Glutamates: Norep

dezoksy [38]

Answer:

Serotonin

___________

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3 years ago

When a fluid is heated, what changes occur?

lisov135 [29]

The answer to this question is A. It becomes less dense and begins to rise.

8 0

3 years ago

Ethan pushes a wooden box across a carpeted floor. Then he pushes the same box across a smooth marble floor. Why does Ethan find

Ksju [112]

Answer:

B.The box experiences less friction on the marble floor

Explanation:

8 0

3 years ago

Read 2 more answers

The rate at which a metal alloy oxidizes in an oxygen-containing atmosphere is a typical example of the practical utility of the

Ray Of Light [21]

Answer:

The activation energy is $Q = 328.31 \ K J/mol$

Explanation:

From the question we are told that

The rate constant is k

at the temperature $T_1 = 300 = 300 + 273 = 573 \ K$

The value of k is $k_1 = 1.05 *10^{-8} \ kg /m^4 \cdot s$

at temperature $T_2 = 400 ^oC = 400 + 273 = 673 \ K$

The value of k is $k_2 = 2.95 *10^{-4} \ kg /m^4 \cdot s$

The rate constant is mathematically represented as

$k = Ce^{- \frac{Q}{RT} }$

Where Q is the activation energy

R is the ideal gas constant with a value of $R = 8.314 \ J /mol \cdot K$

C is a constant

T is the temperature

For the first rate constant

$k_1 = Ce ^{-\frac{Q}{RT_1} }$

For the second rate constant

$k_2 = Ce ^{-\frac{Q}{RT_2} }$

Now the ratio between the two given rate constant is

$\frac{k_1 }{k_2} = e^{(\frac{Q}{R} [\frac{1}{\frac{T_2 - 1}{T_1} } ] )}$

=> $ln [\frac{k_1}{k_2} ] = \frac{Q}{R} * [\frac{1}{\frac{T_2 -1}{T_1} } ]$

substituting values

$ln [\frac{1.05 *10^{-8}}{2.95 *10^{-4}} ] = \frac{Q}{8.314} * [\frac{1}{\frac{673 -1}{573} } ]$

=> $Q = 328.31 \ K J/mol$

7 0

3 years ago