The answers false I believe
10/70×360°
=51.4°
hope thus helps
Explanation:
can u pls ask the question again? No full information! I mean are you required the time it takes or what ?
Answer:
The magnitude of the external electric field at P will reduce to 2.26 x 10⁶ N/C, but the direction is still to the right.
Explanation:
From coulomb's law, F = Eq
Thus,
F = E₁q₁
F = E₂q₂
Then
E₂q₂ = E₁q₁

where;
E₂ is the external electric field due to second test charge = ?
E₁ is the external electric field due to first test charge = 4 x 10⁶ N/C
q₁ is the first test charge = 13 mC
q₂ is the second test charge = 23 mC
Substitute in these values in the equation above and calculate E₂.

The magnitude of the external electric field at P will reduce to 2.26 x 10⁶ N/C when 13 mC test charge is replaced with another test charge of 23 mC.
However, the direction of the external field is still to the right.
Answer:
Explanation:
density of galaxies would be
times higher which is equal to 50.81.
It means in a cube that today contains one galaxy the size of the Milky Way, we would instead find 50.81 galaxies this size.
You can round this off to 52