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spin [16.1K]
2 years ago
8

Which graph shows the inverse of the graph of X^2 ​

Mathematics
1 answer:
wariber [46]2 years ago
6 0
Your answer should be C. If you put x^2 in a graph it looks like graph B. However we are looking for the inverse or the opposite so it’ll be C.
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Find the slope and y-intercept of y=-5
kicyunya [14]

Answer:

slope = 0

y intercept = -5

Step-by-step explanation:

y= -5  is a horizontal line

horizontal lines have a slope of 0

it crosses the x axis at y=-5


4 0
3 years ago
Read 2 more answers
Jameson Flip a quarter two times in a row. What is the probability that he flipped a heads followed by a tails?
Vadim26 [7]

Answer:

1/4

Step-by-step explanation:

5 0
3 years ago
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The length of an object is measured as 34.8 centimeters. What is this measurement in scientific notation?
harkovskaia [24]

Answer:

34.8 x 10 to the power of 0.

Step-by-step explanation:

hope this helps

3 0
2 years ago
What is the value of the function f(x) = 2x – 5 when x = 22? A17 B49 C105 D39
enyata [817]
<span>f(x) = 2x – 5

</span><span>f(22) = 2(22) – 5 = 44 -5 = 39

answer

</span><span>D39</span>
8 0
3 years ago
A veterinary researcher takes a random sample of 60 horses presenting with colic. The average age of the random sample of horses
Licemer1 [7]

Answer:

Probability that a sample mean is 12 or larger for a sample from the horse population is 0.0262.

Step-by-step explanation:

We are given that a veterinary researcher takes a random sample of 60 horses presenting with colic. The average age of the random sample of horses with colic is 12 years. The average age of all horses seen at the veterinary clinic was determined to be 10 years. The researcher also determined that the standard deviation of all horses coming to the veterinary clinic is 8 years.

So, firstly according to Central limit theorem the z score probability distribution for sample means is given by;

                    Z = \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } } ~ N(0,1)

where, \bar X = average age of the random sample of horses with colic = 12 yrs

            \mu = average age of all horses seen at the veterinary clinic = 10 yrs

   \sigma = standard deviation of all horses coming to the veterinary clinic = 8 yrs

         n = sample of horses = 60

So, probability that a sample mean is 12 or larger for a sample from the horse population is given by = P(\bar X \geq 12)

   P(\bar X \geq 12) = P( \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } } \geq \frac{12-10}{\frac{8}{\sqrt{60} } } ) = P(Z \geq 1.94) = 1 - P(Z < 1.94)

                                                 = 1 - 0.97381 = 0.0262

Therefore, probability that a sample mean is 12 or larger for a sample from the horse population is 0.0262.

4 0
3 years ago
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