Answer:
Does liquid HF conduct electricity?
Explanation:
HF is the precursor to elemental fluorine, F2, by electrolysis of a solution of HF and potassium bifluoride. The potassium bifluoride is needed because anhydrous HF does not conduct electricity.
Answer:
Number of produced moles of carbondioxide is 0.113 mol.
Explanation:
Excess of sulphuric acid is present.And the sodium carbonate is completely consumed.
Molar mass of sodium carbonate = 105.99g/mol
Given mass of sodium carbonate =12 g/mol
one mole of sodium carbonate produce one mole of carbondioxide.
0.113 mole of sodium carbonate produce 0.113 mole of carbondioxide.
Therefore, 0.113 mol of carbondioxide produced in flask 7.
Answer:
Mass = 36.38 g
Explanation:
Given data:
Mass of hydrogen = 30.0 g
Mass of nitrogen = 30.0 g
Theoretical yield of reaction = ?
Mass of ammonia = ?
Chemical equation:
N₂+ 3H₂ → 2NH₃
Number of moles of N₂:
Number of moles = Mass /molar mass
Number of moles = 30 g / 28 g/mol
Number of moles = 1.07 mol
Number of moles of H₂:
Number of moles = Mass /molar mass
Number of moles = 30 g / 2g/mol
Number of moles = 15 mol
Now we will compare the moles of NH₃ with hydrogen and nitrogen .
H₂ : NH₃
3 : 2
15 : 2/3×15= 10 mol
N₂ : NH₃
1 : 2
1.07 : 2 × 1.07= 2.14 mol
The number of moles of NH₃ produced by nitrogen are less it will be limiting reactant.
Mass of ammonia:
Mass of NH₃ = moles × molar mass
Mass =2.14 mol × 17 g/mol
Mass = 36.38 g
Answer:
A. iodine
C. fluorine
F. bromine
Explanation:
Ionic bonds occur mostly between metals and non-metals. Usually, a wide electronegativity difference is preferred between the two atoms. This makes one atom more desirous to gain electron and other more willing to donate electrons.
To have Zn forming a compound in the ratio of 1 to 2, the combining power must be similar to this.
The dominant oxidation state of Zn is the is the +2 state.
The other combining atoms must have the ability to recieve the two electrons.
The halogens fit perfectly into this picture. They need just an electron to attain nobility. They are also highly electronegative. If two halogens combines with the Zn, then the ionic bond will result.
The halogens are fluorine,chlorine, bromine, iodine and astatine.
They will form these compounds:
ZnF₂, ZnBr₂ and ZnI₂