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Nina [5.8K]
3 years ago
5

Please help, basic algebra. Find the value of x

Mathematics
1 answer:
Naily [24]3 years ago
8 0

Answer:

<em>76 degrees</em>

Step-by-step explanation:

The corresponding angles help you solve this.

The vertical angle of x (meaning the one practically in front of it) is 76 degrees, since x is vertical to 76, the degree will be the same.

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NEED ASAP
nadya68 [22]

Answer:

$0.29

Step-by-step explanation:

Multiply the unit weight ($0.24/ounce) by the weight (1.2 oz.):

$0.24     1.2 oz

.24 * 1.2 = $0.288

So, the rounded answer will be $0.29

5 0
3 years ago
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What is the domain of the square root function graphed below?
melisa1 [442]
You can see that the function is graphed for every number x that is greater than or equal to zero.

So we write that the domain is x \leq 0.
4 0
3 years ago
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Um soo they make me do dis but pls help? 14 points
Agata [3.3K]

Answer:

3 more than

Step-by-step explanation:

Hope this correct and Your welcome

7 0
3 years ago
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Perform the indicated row operations, then write the new matrix.
Studentka2010 [4]

The matrix is not properly formatted.

However, I'm able to rearrange the question as:

\left[\begin{array}{ccc}1&1&1|-1\\-2&3&5|3\\3&2&4|1\end{array}\right]

Operations:

2R_1 + R_2 ->R_2

-3R_1 +R_3 ->R_3

Please note that the above may not reflect the original question. However, you should be able to implement my steps in your question.

Answer:

\left[\begin{array}{ccc}1&1&1|-1\\0&5&7|1\\0&-1&1|4\end{array}\right]

Step-by-step explanation:

The first operation:

2R_1 + R_2 ->R_2

This means that the new second row (R2) is derived by:

Multiplying the first row (R1) by 2; add this to the second row

The row 1 elements are:

\left[\begin{array}{ccc}1&1&1|-1\end{array}\right]

Multiply by 2

2 * \left[\begin{array}{ccc}1&1&1|-1\end{array}\right] = \left[\begin{array}{ccc}2&2&2|-2\end{array}\right]

Add to row 2 elements are: \left[\begin{array}{ccc}-2&3&5|3\end{array}\right]

\left[\begin{array}{ccc}2&2&2|-2\end{array}\right] + \left[\begin{array}{ccc}-2&3&5|3\end{array}\right]

\left[\begin{array}{ccc}0&5&7|1\end{array}\right]

The second operation:

-3R_1 +R_3 ->R_3

This means that the new third row (R3) is derived by:

Multiplying the first row (R1) by -3; add this to the third row

The row 1 elements are:

\left[\begin{array}{ccc}1&1&1|-1\end{array}\right]

Multiply by -3

-3 * \left[\begin{array}{ccc}1&1&1|-1\end{array}\right] = \left[\begin{array}{ccc}-3&-3&-3|3\end{array}\right]

Add to row 2 elements are: \left[\begin{array}{ccc}3&2&4|1\end{array}\right]

\left[\begin{array}{ccc}-3&-3&-3|3\end{array}\right] + \left[\begin{array}{ccc}3&2&4|1\end{array}\right]

\left[\begin{array}{ccc}0&-1&1|4\end{array}\right]

Hence, the new matrix is:

\left[\begin{array}{ccc}1&1&1|-1\\0&5&7|1\\0&-1&1|4\end{array}\right]

3 0
3 years ago
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A store employee conducted a survey of 390 randomly selected customers. According to the survey, 180 of the customers often use
shusha [124]
You do 390/100 = 180/x then 390×X=390X
180×100=18000
390X=18000
390X÷390=X
18000÷390=46.15384615=46%
7 0
3 years ago
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