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4 years ago

5

Why do nurses need to understand chemistry?

1 answer:

blagie [28]4 years ago

4 0

Answer:

D.)Chemistry helps them understand how medicines work.

The subject is spread over one or two semesters and it deals with the structure of atoms, molecules and other compounds. Nursing students need to have a good knowledge of this type of chemistry because it deals with organic matter and its reaction to different kinds of chemicals

https://www.globalpremeds.com/blog/2014/08/14/why-do-nursing-students-have-to-study-chemistry/

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How many miles of water are produced if 5.43 mol PBO2 are consumed

bija089 [108]

Answer:

Amount of oxygen = 2 * 5.43 moles

= 10.86 moles

Explanation:

7 0

3 years ago

Read 2 more answers

20.0g of H2(g) and 32g of O2(g) are reacted produce H2O(l). The amount of hydrogen left behind after completion of reaction is?

Hitman42 [59]

Answer:

8 moles = 16 gm of H2 left over

Explanation:

The balanced equation is

2 H2 + O2 ===> 2 H2 O

20 g H2 = 20 g / 2 gm/mole = 10 moles of H2

32 g O2 = 32g / 32 g / mole = 1 mole O2

From the balanced equation, you can see each 2 moles of H2 requires 1 Mole of O2

you would need 20 moles of O 2 to react withe the 10 moles of H2

but you only have 1 mole of O2 so 8 moles of H2 will be left

5 0

2 years ago

The following physical constants are for water, H2O.

Delicious77 [7]

Answer:

$Q\approx6.4~kJ$

Explanation:

Quantity of heat required by 10 gram of ice initially warm it from -5°C to 0°C:

$Q_1=m.C_s.\Delta T$

here;

mass, m = 10 g

specific heat capacity of ice, $C_s=2.09~J.g^{-1}.^{\circ}C^{-1}$

change in temperature, $\Delta T=(5-0)=5^{o}C$

$Q_1=10\times2.09\times 5$

$Q_1=104.5~J$

Amount of heat required to melt the ice at 0°C:

$Q_2=m.\Delta H_{fus}$

where, $\Delta H_{fus}=6020~J/mol$

we know that no. of moles is = (wt. in gram) $\div$ (molecular mass)

$Q_2=\frac{10}{18} \times 6020$

$Q_2=3344.44~J$

Now, the heat required to bring the water to 70°C from 0°C:

$Q_3=m.C_L.\Delta T$

specific heat of water, $C_L=4.18~J/g/^oC$

change in temperature, $\Delta T=(70-0)=70^oC$

$Q_3=10\times 4.18\times 70$

$Q_3=2926~J$

Therefore the total heat required to warm 10.0 grams of ice at -5.0°C to a temperature of 70.0°C:

$Q=Q_1+Q_2+Q_3$

$Q=104.5+3344.44+2926$

$Q=6374.94~J$

$Q\approx6.4~kJ$

8 0

4 years ago

Pyrite has a metallic luster. which sample is most likely pyrite?

kupik [55]

Answer:

C

Explanation:

others are boring or gems

7 0

3 years ago

Read 2 more answers

NaBr (aq) + _H3PO4 (aq) → _Na3PO4(aq) + _HBr (aq)<br> 3,1,1,3<br> 1,2,3,1<br> 3,1,3,1<br> 1,1,3,3

BaLLatris [955]

Answer:

A 3,1,1,3

Explanation:

hope the picture help u to understand :)

6 0

3 years ago