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EastWind [94]
3 years ago
8

Which half-reaction correctly represents reduction?

Chemistry
1 answer:
Neko [114]3 years ago
5 0

Answer: B. Ca2+   +  2e- --------->   Ca

Explanation:

Reduction involves the gaining of electrons as well as a decrease in the oxidation state of the atom or ion.

In this case; Ca2+ gains two electrons and the oxidation state is reduced from +2 to  0.

Ca2+   +  2e- --------->   Ca

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Why do some elements form double and triple bonds during bonding
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Consider the following unbalanced chemical equation. C5H12(l) + O2(g) → CO2(g) + H2O(l) If 21.9 grams of pentane (C5H12) are bur
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Answer : The mass of water produced will be 32.78 grams.

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Mass of C_5H_{12} = 21.9 g

Molar mass of C_5H_{12} = 72.15 g/mole

Molar mass of H_2O = 18 g/mole

First we have to calculate the moles of C_5H_{12}.

\text{Moles of }C_5H_{12}=\frac{\text{Mass of }C_5H_{12}}{\text{Molar mass of }C_5H_{12}}=\frac{21.9g}{72.15g/mole}=0.3035moles

Now we have to calculate the moles of H_2O.

The balanced chemical reaction will be,

C_5H_{12}(l)+8O_2(g)\rightarrow 5CO_2(g)+6H_2O(l)

From the balanced reaction we conclude that

As, 1 mole of C_5H_{12} react to give 6 moles of H_2O

So, 0.3035 moles of C_5H_{12} react to give 0.3035\times 6=1.821 moles of H_2O

Now we have to calculate the mass of H_2O.

\text{Mass of }H_2O=\text{Moles of }H_2O\times \text{Molar mass of }H_2O

\text{Mass of }H_2O=(1.821mole)\times (18g/mole)=32.78g

Therefore, the mass of water produced will be 32.78 grams.

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3 years ago
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