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ehidna [41]
3 years ago
7

A large container of water and a small one are at the same temperature. What can be said about the relative vapor pressures of t

he water in the two containers?
Chemistry
1 answer:
LenaWriter [7]3 years ago
6 0

Answer:

The relative vapor pressure in both containers is the same

Explanation:

<em>Vapor pressure</em> is a property that indicates a liquid's evaporation rate. This property is not dependant on surface area or volume of liquid. So as long as the large container and the small container are at the same temperature, the relative vapor pressure of water will be the same.

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2. A sample of neon gas has a volume of 87.6 L at STP. How many moles are present?
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Answer:

                      3.91 moles of Neon

Explanation:

According to Avogadro's Law, same volume of any gas at standard temperature (273.15 K or O °C) and pressure (1 atm) will occupy same volume. And one mole of any Ideal gas occupies 22.4 dm³ (1 dm³ = 1 L).

Data Given:

                 n = moles = <u>???</u>

                 V = Volume = 87.6 L

Solution:

               As 22.4 L volume is occupied by one mole of gas then the 16.8 L of this gas will contain....

                          = ( 1 mole × 87.6 L) ÷ 22.4 L

                          = 3.91 moles

<h3>2nd Method:</h3>

                     Assuming that the gas is acting ideally, hence, applying ideal gas equation.

                              P V  =  n R T      ∴  R  =  0.08205 L⋅atm⋅K⁻¹⋅mol⁻¹

Solving for n,

                              n  =  P V / R T

Putting values,

                              n  =  (1 atm × 87.6 L)/(0.08205 L⋅atm⋅K⁻¹⋅mol⁻¹ × 273.15K)

                              n  =  3.91 moles

Result:

          87.6 L of Neon gas will contain 3.91 moles at standard temperature and pressure.

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Suppose you combine two substances but no chemical reaction occurs. Which of the following best describes the result?
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