Draw the structures of the starting materials needed to make 2‑methylhept‑3‑yne or 2‑methyl‑3‑heptyne. The starting materials ma
1 answer:
Answer:
Explanation:
The structures of the starting materials 2‑methylhept‑3‑yne can be seen in the diagram attached below. We will also notice the role of NaNH₂ which acts as a strong base and whose function is to extract acidic proton and form an alkyne as a product.
The reaction with NaNH₂ yields acetylide ion which is then reacted with a straight-chain alkyl halide to form an extended carbon chain.
CHECK THE DIAGRAM BELOW.
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Answer:
You need 8,324 g of CaCl₂ yo make this solution
Explanation:
Molarity is a way to express concentration in a solution, in units of moles of solute per liter of solution.
To know the grams of CaCl₂ it is necessary to know, first, the moles of this substance with the desired volume and concentration , thus:
0,1500 L × = 0,075 CaCl₂ moles
Now, with the molar mass of CaCl₂ you will obtain the necessary grams, thus:
0,075 CaCl₂ moles × = 8,324 g of CaCl₂
So, you need <em>8,324 g of CaCl₂</em> to make 150,0 mL of a 0,500M solution
I hope it helps!