These atoms are isotopes, they have the same number of protons which means the atoms are of the same ELEMENT, but they have different numbers of neutrons.
Answer:
A
Explanation:
The only factor that would not decrease the carrying capacity of the fur seal's environment is the population of predators.
<em>The carrying capacity is defined as the maximum number of individuals of a species an environment can sustain based on the resources available. Hence, only a fluctuation in the resources available in the environment of the fur seal can affect the carrying capacity. </em>
<u>Pollution </u>and <u>destruction of the habitat of the fur seal</u> would limit the resources available to the animals and as such, limit the carrying capacity. A <u>fluctuation in the population of prey available</u> for the population of fur seals would also affect the carrying capacity.
The only factor that has no bearing on the carrying capacity of the fur seal's environment is the population of predators. Predators have the capacity to reduce the population of fur seals but not affect the carrying capacity for fur seals.
The correct option is, therefore, A.
Answer:
The volume of the gas at 100°C is 4.6189 liters.
Explanation:
For this problem we are going to use Charles' law. Charles' law states that the volume is directly proportional to temperature given that the pressure is constant. In order to use the equation, the unit of temperature should be in Kelvin.
The working equation is:
=
where V1 and T1 are the initial volume and temperature while V2 and T2 are the final conditions.
Let us convert first the temperatures before solving for the final volume.
To convert Celsius to Kelvin just add 273.15 to temperature in Celsius.
50°C + 273.15 = 323.15 K
100°C + 273.15 = 373.15 K
Solving for the final volume:
V₂ =
V₂ =
V₂ = 4.6189 L
Therefore the final volume of the gas at 100°C is 4.6189 L.
Explanation:
Answer:
Ola tudo bem??
Meu nome é Ana Kesia, e o seu?
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Boa tarde, Tchau.
Answer:
80.7 L
Explanation:
PV = nRT
P = 1520 mmHg = 2 atm
n = 5 mol
R = 0.08206 (L * atm)/(mol * K)
T = 393.15 K
2 (V) = 5 (0.08206) (393.15)
V ≈ 80.7 L
