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Romashka [77]
3 years ago
13

How many isomeric dichloro products can be obtained from the chlorination of cyclopropane?

Chemistry
1 answer:
Allushta [10]3 years ago
8 0

Answer:

Three isomers

Explanation:

Cyclopropane undergoes addition reaction with chlorine to form dichlorocyclopropane.

Three isomeric forms are possible for dichlorocyclopropane.

1. 1,1-dichlorocyclopropane

2. cis-1,2 dichlorocyclopropane

3. trans-1,2 dichloropropane

1,1-dichorocyclopropane ans 1, 2-dichloropropane are structural isomers whereas cis-1,2 dichlorocyclopropane and trans-1,2 dichloropropane are geometrical isomers of each other.

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How would a bar magnet orient itself relative to this planet's magnetic field?
Maksim231197 [3]

The magnet's north pole would point to the Earth's south pole and the magnet's south pole would point to the Earth's north pole.

<u>Explanation</u>:

  • There is a magnetic pole in the earth and the magnetic poles of the earth run using the equator and it has both the closures at the arctic pole and the Antarctic pole. The attractive positive field or the north pole is situated in the arctic zone and the south pole is situated in the Antarctic zone.  
  • The magnetic positive field or the north pole is situated in the arctic zone. Any magnet which is allowed to rotate whenever suspended on the outside of the earth will align itself with the magnetic field of the earth. That is the way the bar magnet orients itself comparative with this current planet's magnetic field.
7 0
3 years ago
What is the difference between a helium atom and an alpha particle​
artcher [175]

Answer:

???????

????

Explanation:

4 0
3 years ago
When an atom of N-14 is bombarded by an alpha particle, the single product is
puteri [66]

Answer:

¹⁸F₉

Explanation:

  • Alpha particles contain 2 protons and 2 neutrons, that is 4/2.
  • Which mains that the number of protons and neutrons will increase by 2.
  • So, the single product will be ¹⁸F₉.
6 0
3 years ago
Write balanced net ionic equations and the corresponding equilibrium equations for the stepwise dissociation of the triprotic ac
Elza [17]

Answer:

H_3PO_4(aq)+H_2O(l)\rightleftharpoons H_3O^+(aq)+H_2PO_4^{-}(aq); \ Ka_1

H_2PO_4^{-}(aq)+H_2O(l)\rightleftharpoons H_3O^+(aq)+HPO_4^{-2}(aq); \ Ka_2

HPO_4^{-2}(aq)+H_2O(l)\rightleftharpoons H_3O^+(aq)+PO_4^{-3}(aq); \ Ka_3

Explanation:

Hello!

In this case, since the phosphoric acid is a triprotic acid, we infer it has three stepwise ionization reactions in which one hydrogen ion is released at each step, considering they are undergone due to the presence of water, thus, we proceed as follows:

H_3PO_4(aq)+H_2O(l)\rightleftharpoons H_3O^+(aq)+H_2PO_4^{-}(aq); \ Ka_1

H_2PO_4^{-}(aq)+H_2O(l)\rightleftharpoons H_3O^+(aq)+HPO_4^{-2}(aq); \ Ka_2

HPO_4^{-2}(aq)+H_2O(l)\rightleftharpoons H_3O^+(aq)+PO_4^{-3}(aq); \ Ka_3

Moreover, notice each step has a different acid dissociation constant, which are quantified in the following order:

Ka1 > Ka2 > Ka3

Best regards!

3 0
3 years ago
Microscale glassware kits include connectors to fit the smaller glassware. The black connectors should be used when _________ ar
spayn [35]

Answer:

high boiling aromatics

with the same ground glass joint.

Explanation:

The black connectors are more resistant to the reactant than the white connectors. This implies that the black connectors should be used when high boiling aromatics are present, Else, the tan connections can be used.

Thus, the connectors can combine different pieces of glassware or components <u>with the same ground glass joint.</u>

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6 0
3 years ago
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