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ozzi
3 years ago
5

Simplify √49 + [√81 - x(9x = 14)]

Mathematics
1 answer:
eimsori [14]3 years ago
3 0

\longrightarrow{\green{- 9 {x}^{2}   +  14x + 16}} 

\large\mathfrak{{\pmb{\underline{\red{Step-by-step\:explanation}}{\orange{:}}}}}

\sqrt{49}  + [ \sqrt{81} - x \: (9x   -  14) ] \\ \\   =  \sqrt{7 \times 7}  + [ \sqrt{9 \times 9}   - 9 {x}^{2}   +  14x] \\  \\  =  \sqrt{( {7})^{2} }  + [ \sqrt{ ({9})^{2} }  - 9 {x}^{2}  +  14x ] \\  \\  (∵ \sqrt{ ({x})^{2} } = x ) \\  \\  = 7 + (9 - 9 {x}^{2}   + 14x) \\  \\  = 7 + 9 - 9 {x}^{2}   + 14x \\  \\  =  - 9 {x}^{2}   +  14x + 16

\large\mathfrak{{\pmb{\underline{\orange{Mystique35 }}{\orange{♡}}}}}

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Luiza is jumping on a trampoline.
lyudmila [28]

Answer:

The second time when Luiza reaches a height of 1.2 m = 2 08 s

Step-by-step explanation:

Complete Question

Luiza is jumping on a trampoline. Ht models her distance above the ground (in m) t seconds after she starts jumping. Here, the angle is entered in radians.

H(t) = -0.6 cos (2pi/2.5)t + 1.5.

What is the second time when Luiza reaches a height of 1.2 m? Round your final answer to the nearest hundredth of a second.

Solution

Luiza is jumping on trampolines and her height above the levelled ground at any time, t, is given as

H(t) = -0.6cos⁡(2π/2.5)t + 1.5

What is t when H = 1.2 m

1.2 = -0.6cos⁡(2π/2.5)t + 1.5

0.6cos⁡(2π/2.5)t = 1.2 - 1.5 = -0.3

Cos (2π/2.5)t = (0.3/0.6) = 0.5

Note that in radians,

Cos (π/3) = 0.5

This is the first time, the second time that cos θ = 0.5 is in the fourth quadrant,

Cos (5π/3) = 0.5

So,

Cos (2π/2.5)t = Cos (5π/3)

(2π/2.5)t = (5π/3)

(2/2.5) × t = (5/3)

t = (5/3) × (2.5/2) = 2.0833333 = 2.08 s to the neareast hundredth of a second.

Hope this Helps!!!

4 0
3 years ago
What is the domain of the function y=in(x+2) x<-2 x>-2 x<2 x> x<-2 x>-2 x<2 x>2
aev [14]

For this case we must find the domain of the following function:

y = ln (x + 2)

By definition, the domain of a function is given by all the values for which the function is defined.

In this case, the argument of the expression must be greater than 0 to be defined.

x + 2> 0\\x> -2

Thus, the domain of the function is given by all the values of x greater than -2.

Answer:

Domain: x> -2

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Step-by-step explanation:

.......................

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