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2 years ago

12

: To determine the focal length of a lens, the following except _ is needed

1 answer:

mixer [17]2 years ago

4 0

The answer should besiphon

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Calculate curls of the following vector functions (a) AG) 4x3 - 2x2-yy + xz2 2

aleksandr82 [10.1K]

Answer:

The curl is $0 \hat x -z^2 \hat y -4xy \hat z$

Explanation:

Given the vector function

$\vec A (\vec r) =4x^3 \hat{x}-2x^2y \hat y+xz^2 \hat z$

We can calculate the curl using the definition

$\nabla \times \vec A (\vec r ) = \left|\begin{array}{ccc}\hat x&\hat y&\hat z\\\partial/\partial x&\partial/\partial y&\partial/\partial z\\A_x&X_y&A_z\end{array}\right|$

Thus for the exercise we will have

$\nabla \times \vec A (\vec r ) = \left|\begin{array}{ccc}\hat x&\hat y&\hat z\\\partial/\partial x&\partial/\partial y&\partial/\partial z\\4x^3&-2x^2y&xz^2\end{array}\right|$

So we will get

$\nabla \times \vec A (\vec r )= \left( \cfrac{\partial}{\partial y}(xz^2)-\cfrac{\partial}{\partial z}(-2x^2y)\right) \hat x - \left(\cfrac{\partial}{\partial x}(xz^2)-\cfrac{\partial}{\partial z}(4x^3) \right) \hat y + \left(\cfrac{\partial}{\partial x}(-2x^2y)-\cfrac{\partial}{\partial y}(4x^3) \right) \hat z$

Working with the partial derivatives we get the curl

$\nabla \times \vec A (\vec r )=0 \hat x -z^2 \hat y -4xy \hat z$

6 0

3 years ago

What is the formula to find initial velocity?

Inga [223]

Answer:

s = ut + 1/2at^2

Explanation:

s= distance

u= initial velocity

a= acceleration

7 0

2 years ago

Describe liquids and GASSES IN TERMS OF THERE VOLUME AND SHAPES

antiseptic1488 [7]

Answer:

Explanation:

liquids have definite volume

liquids do not have definite shape. The take the shape of the container in which they are kept.

gases do not have definite volume.

gases do not have definite shape. They take the shape of the container in which they are kept.

Hope this helps

plz mark as barinliest!!!!!!

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3 0

2 years ago

Read 2 more answers

Aiden has basketball practice after school on Mondays, Wednesdays, and Fridays. He has practiced really hard this year to get be

Jlenok [28]

Ok I’ll help you I think 20 -192 = 1928172 then ur divided • by 181$1 then u get 244141551611671718181919191827337533535352526

6 0

2 years ago

A mobile phone is 35% efficient. Over half an hour 11 kJ of energy is transferred to the phone.

kramer

<h3><u>A</u><u>n</u><u>s</u><u>w</u><u>e</u><u>r</u><u>:</u><u>-</u></h3>

Energy Transferre=11KJ
Efficiency=35%

<h3>☆Usefully transferred energy:-</h3>

$\\ \sf\longmapsto 35\%\:of 11$

$\\ \sf\longmapsto 35\%\times 11$

$\\ \sf\longmapsto \dfrac{35}{100}\times 11$

$\\ \sf\longmapsto \dfrac{385}{100}$

$\\ \sf\longmapsto 3.85KJ$

$\\ \sf\longmapsto 3850J$

6 0

2 years ago