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likoan [24]
3 years ago
15

A loading car is at rest on a track forming an angle of 25° with the vertical. The gross weight of the car and its load is 5500

lbf, and it is applied at a point 30 in. from the track, halfway between the two axles. The car is held by a cable attached 24 in. from the track. Determine the tension in the cable and the reaction at each pair of wheels (that is determine the forces exerted by the track surface on the wheels of the car; note that wheels are part of the car, do not consider them separately
Physics
1 answer:
koban [17]3 years ago
4 0
Idk I just need other answers
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A light with a second-order bright band forms a diffraction angle of 30. 0°. The diffraction grating has 250. 0 lines per mm. Wh
Luden [163]

The distance between two successive troughs or crests is known as the wavelength. The wavelength of the light will be 1000 nm.

How do you define wavelength?

The distance between two successive troughs or crests is known as the wavelength. The peak of the wave is the highest point, while the trough is the lowest.

The wavelength is also defined as the distance between two locations in a wave that have the same oscillation phase.

Diffraction angle= 30⁰

Diffraction grating per mm= 250

wavelength = ?

Mathematically the equation of bright band is given by

\rm \lambda= \frac{sin\theta}{nN}

\rm \lambda= \frac{sin23^0}{250\times 2}

\rm \lambda= 0.000001 m

\rm \lambda= 1000 nm

Hence the wavelength of the light will be 1000 nm.

To learn more about the wavelength refer to the link;

brainly.com/question/7143261

8 0
2 years ago
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A light ray strikes a flat, smooth, reflecting surface at an angle of 80° to the normal. What angle does
charle [14.2K]

Answer:

80 angle of incidence=angle of reflection

Explanation:

7 0
3 years ago
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What is the pressure exerted when a force of 20 N is applied to an object over an area of 2 m2 ?
IgorC [24]

(20 N)/(2 m²) = (20/2) N/m² = 10 Pa

_____

The pascal (Pa) is the derived SI unit of pressure equal to 1 N/m².

8 0
3 years ago
If a creature cats Ferrari, with an initial speed of 10 m/s, accelerate at a rate of 50 m/s/s for 3 seconds, what will it's fina
riadik2000 [5.3K]


160 m/s because you start off with 10 and go up by 50*3 which is 150 then add that with the begging speed to achieve 160m/s.

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A 140 kg load is attached to a crane, which moves the load vertically. Calculate the tension in the cable for the following case
Murljashka [212]

Answer:

The answer is below

Explanation:

A 140 kg load is attached to a crane, which moves the load vertically. Calculate the tension in the

cable for the following cases:

a. The load moves downward at a constant velocity

b. The load accelerates downward at a rate 0.4 m/s??

C. The load accelerates upward at a rate 0.4 m/s??

Solution:

Acceleration due to gravity (g) = 10 m/s²

a) Given that the mass of the crane (m) is 140 kg. If the load moves downward, the tension (T) is given by:

mg - T = ma

Since the load has a constant velocity, hence acceleration (a) = 0. Therefore:

mg - T = m(0)

mg - T = 0

T = mg

T = 140(10) = 1400 N

T = 1400 N

b)  If the load moves downward, the tension (T) is given by:

mg - T = ma

T = mg - ma = m(g - a)

T = 140(10 - 0.4) = 140(9.96) = 134.4

T = 134.4 N

c)  If the load moves upward, the tension (T) is given by:

T - mg = ma

T = ma + mg = m(a + g)

T = 140(0.4 + 10) = 140(10.4)

T = 145.6 N

2) To find the distance (s) if the load move from rest (u= 0) and accelerates for 20 seconds (t = 20). We use:

s = ut + (1/2)gt²

s = 0(20) + (1/2)(10)(20)²

s = 2000 m

7 0
3 years ago
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