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Crank
2 years ago
6

5. A ball weighing 10 kg rolls 200 m down a frictionless incline with a 50 degree angle to the horizontal. If the ball’s initial

velocity was 0 m/s, how much does the mechanical energy of the system change by the time the ball reaches its destination? A) It increased by 12%. B) It increases by 58%. C) It decreases by 12%. D) It does not change.
Physics
1 answer:
sdas [7]2 years ago
3 0

Answer:

D) It does not change

Explanation:

Since there is no friction in the inclined plane. Therefore, there is no loss in the total mechanical energy of the system. So according to the law of conservation of energy we can write:

Total Mechanical Energy at Start = Total Mechanical Energy at End + Frictional Loss

Total Mechanical Energy at Start = Total Mechanical Energy at End + 0

Total Mechanical Energy at Start = Total Mechanical Energy at End

It means there is no change in the total mechanical energy of the system.

Therefore, the correct option is:

<u>D) It does not change</u>

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Assuming that all the bullet’s energy heats the paraffin, its final temperature is 27.1 degree C. The correct option is D.

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Temperature is the degree of hotness and coldness of the material.

The energy of the bullet E = 1/2 mv²

E = 1/2 x 10 x 10⁻³ x (2000)²

E = 2 x 10⁴ J

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2 x 10⁴ J = 1 x 2.8 x 10³ x (Tfinal -20)

Tfinal = 27.1°C

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The density of a substance equals its mass divided by its volume. Talia listed the density of some common materials at 20 °C.
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A person walks 9.0 km directly east and then turns left and heads directly north for 12.0 km. What is his displacement from the
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Explanation:

Given that,

A person walks 9.0 km directly east and then turns left and heads directly north for 12.0 km.

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We know that,

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