5. A ball weighing 10 kg rolls 200 m down a frictionless incline with a 50 degree angle to the horizontal. If the ball’s initial
1 answer:
You might be interested in
According to Newton`s law. Force exerted by car,
After adding an additional 400 kg of mass, the force will be same therefore the acceleration
Thus, the acceleration after adding the masses is 1.47 \ m/s^2.
Hi there!
We can begin by calculating the time the ball takes to reach the highest point of its trajectory, which can be found using the following:
Where:
tmax = (? sec)
vsinθ = vertical comp. of velocity = 10sin(48) = 7.43 m/s)
g = acceleration due to gravity (9.8 m/s²)
We can solve for this time:
When the ball is at the TOP of its trajectory, its VERTICAL velocity is equivalent to 0 m/s. Thus, we can consider this a free-fall situation.
We must begin by solving for the maximum height reached by the ball using the equation:
d = displacement (m)
vi = initial velocity (7.43 m/s)
a = acceleration due to gravity
d = displacement (m)
y0 = initial VERTICAL displacement (28m)
Plug in the values:
Now, we can use the rearranged kinematic equation:
Add the two times together: