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Sphinxa [80]
3 years ago
10

Help me pleaseeeeeeeeeeeeeeeeee………….

Mathematics
2 answers:
slava [35]3 years ago
6 0

Answer:

C

Step-by-step explanation:

200 x 5 = 1,000

100 x 10 = 1,000

C - 5 to 10 days

Fynjy0 [20]3 years ago
4 0

Answer:

C. 5 to 10 days

Step-by-step explanation:

If she drove 100 miles per day, then

1000/100 = 10

it took her 10 days.

If she drove 200 miles per day, then

1000/200 = 5

it took her 5 days.

Since she drove between 100 miles and 200 miles per days,

it took her from 5 to 10 days.

Answer: C. 5 to 10 days

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Point D

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Answer: m∠W = 56

because UVWX is a rhombus

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Step-by-step explanation:

7 0
3 years ago
Select the correct answer from each drop-down menu.
Aleks [24]

Answer:

6x^2+5x-6=(3x-2)(2x+3)

Step-by-step explanation:

<u>Given expression</u>:

6x^2+5x-6

To factor a quadratic in the form ax^2+bx+c, first find two numbers that multiply to ac and sum to b:

\implies ac=6 \cdot -6=-36

\implies b=5

Two numbers that multiply to -36 and sum to 5 are: 9 and -4

Rewrite b as the sum of these two numbers:

\implies 6x^2+9x-4x-6

Factorize the first two terms and the last two terms separately:

\implies 3x(2x+3)-2(2x+3)

Factor out the common term (2x + 3):

\implies (3x-2)(2x+3)

Therefore:

6x^2+5x-6=(3x-2)(2x+3)

3 0
2 years ago
Read 2 more answers
An investor in Apple is worried the latest management earnings forecast is too aggressive and the company will fall short. His f
Inga [223]

Answer:

P(GoodR/Below Forecast)= \frac{P(GoodR n Below Forecast)}{P(Below Forecast)}= \frac{0.02}{0.49} = 0.04

Step-by-step explanation:

Hello!

Given the probability information about analyst's report (Good, Medium,  and Bad) and the earnings announcement (Forecast),  you have to calculate the probability that the analyst issued a good report, given that the earnings announcement was "bellow the forecast".

Symbolically: P(Good Report/Below Forecast)

This is a conditional probability, a little reminder:

If you have the events A and B, that are not independent, the probability of A given that B has already happened can be calculated as:

P(A/B)= \frac{P(AnB)}{P(B)}

Where P(A∩B) is the intersection between the two events and P(B) represents the marginal probability of ocurrence of B.

*-*

Using that formula:

P(Good Report/Below Forecast)= \frac{P(Good Report n Below Forecast)}{P(Below Forecast)}

As you can see you have to calculate the value of the probability for the intersection between "Good report" and "Below Forecast" and the probability for P(Below Forecast)

Using the given probability values you can clear the value of the intersection:

P(BelowForecast/Good Report)= \frac{P(Good Report n Below Forecast)}{P(Good Report)}

P(Good Report ∩ Below Forecast)= P(BelowForecast/GoodReport)*P(Good Report)= 0.1*0.2= 0.02

Now the probability of an earnings announcement being "Below Forecast" is marginal, that is if you were to arrange all possible outcomes in a contingency table this probability will be in the marginal sides of the table:

                               Below Forecast

Good Report          P(GoodR∩BelowF)

Medium Report      P(MediumR∩BelowF)

Bad Report             P(BadR∩BelowF)

Total                        P(Below Forecast)

Then P(BelowF)=P(GoodR∩BelowF)+P(MediumR∩BelowF)+P(BadR∩BelowF)

You can clear the two missing probabilities from the remaining information:

P(BelowForecast/MediumR)= \frac{P(BelowForecast n MediumR}{P(MediumR)}

P(BelowF∩MediumR)= P(BelowF/MediumR)*P(MediumR)= 0.4*0.5= 0.2

P(BelowForecast/BadR)= \frac{P(BelowForecastnBadR)}{P(BadR)}

P(BelowF∩BadR)= P(BelowF/BadR)*P(BadR)= 0.9*0.3= 0.27

Now you can calculate the probability of the earning announcement being below forecast:

P(BelowF)=P(GoodR∩BelowF)+P(MediumR∩BelowF)+P(BadR∩BelowF)

P(BelowF)= 0.02+0.2+0.27= 0.49

And finally the asked probability is:

P(GoodR/Below Forecast)= \frac{P(GoodR n Below Forecast)}{P(Below Forecast)}= \frac{0.02}{0.49} = 0.04

I hope this helps!

3 0
3 years ago
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