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nexus9112 [7]
3 years ago
15

Help me!!!Which matrix multiplication is possible?

Mathematics
2 answers:
Ad libitum [116K]3 years ago
7 0

Answer:

guy your picture isn't clear

almond37 [142]3 years ago
5 0

Answer:

The answer is \left[\begin{array}{ccc}1\\-1\\\end{array}\right] * \left[\begin{array}{ccc}0&4\\\end{array}\right].

Step-by-step explanation:

The matrix \left[\begin{array}{ccc}0&3\\\end{array}\right] * \left[\begin{array}{ccc}1&-4\\\end{array}\right]  cannot be multiplied because matrices can only be multiplied if the number of columns in the first matrix is equal to the number of rows in the second matrix.

The matrix \left[\begin{array}{ccc}3\\-2\\\end{array}\right] * \left[\begin{array}{ccc}-1&0\\0&3\\\end{array}\right]  cannot be multiplied because the number of columns in the first matrix is unequal to the number of rows in the second matrix.

The matrix \left[\begin{array}{ccc}1&0\\1&1\\\end{array}\right] * \left[\begin{array}{ccc}3&0\\\end{array}\right]  cannot be multiplied because matrices can only be multiplied if the number of columns in the first matrix is equal to the number of rows in the second matrix.

The matrix \left[\begin{array}{ccc}1\\-1\\\end{array}\right] * \left[\begin{array}{ccc}0&4\\\end{array}\right]  can be multiplied because the number of columns in the first matrix is equal to the number of rows in the second matrix.  The answer to this matrix is \left[\begin{array}{ccc}0&4\\0&-4\\\end{array}\right]. Thus, causing this matrix to be the correct answer to the question.

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