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scoundrel [369]
2 years ago
14

Two large, flat, horizontally oriented plates are parallel to each other, a distance d apart. Half way between the two plates th

e electric field has magnitude E. If the separation of the plates is reduced to d/2 what is the magnitude of the electric field half way between the plates?
a. 0
b. E/2
c. 2E
d. 4E
e. E
Physics
1 answer:
melisa1 [442]2 years ago
8 0

Answer:

E

Explanation:

From the equation describing the Electric field strength of a charge

E=F/q

We can deduce that the electric field strength is dependent on the force arcing on the magnitude of the charge.

As the force increases the the electric field increases, also the electric field strength decreases with increasing charge.

Hence the distance has no effect on the electric field strength. The magnitude remain as E

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A sound wave has a frequency of 425 hz. what is the period of this wave? 0.00235 seconds 0.807 seconds 425 seconds 850 seconds
77julia77 [94]

The period of the sound wave at the given frequency is determined as 0.00235 second.

<h3>Period of the sound wave</h3>

The period of the sound wave at the given frequency is calculated as follows;

Period is reciprocal of frequency.

T = 1/f

T = 1/425

T = 0.00235 second

Thus, the period of the sound wave at the given frequency is determined as 0.00235 second.

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3 0
1 year ago
Jamison walks to a friends house. He walks 1000 meters north, then realizes he walked to far so he turns around and walks 200 me
olasank [31]

We will find that his average velocity is 1.11 m/s north-wise.

<h3>How to get the average velocity?</h3>

We define average velocity as the quotient between the displacement and the time it takes to make that displacement.

We know that he starts at the point 0m, where this measures distance in the north direction.

Then he moves 1000 meters north, so the new position is 1000m.

Then he moves 200 meters south, so the new position is:

1000m - 200m = 800m.

The displacement is equal to the difference between the final position (800m) and the initial position (0m).

D = 800m - 0m = 800m.

And we know that it takes 12 minutes to walk that distance. Because we want the average velocity in meters per second, we write:

12 minutes = 12*(60 seconds) = 720s

Then the average velocity is just:

AV = (800m)/(720s) = 1.11 m/s

And the direction of this average velocity is north-wise.

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4 0
2 years ago
Find the magnitude of the sum
shusha [124]

Answer:

\displaystyle |\vec{v_1}+\vec{v_2}|=4.15m

Explanation:

<u>Sum of Vectors in the Plane</u>

Given two vectors

\displaystyle \vec{v_1}\ ,\ \vec{v_2}

They can be expressed in their rectangular components as

\displaystyle \vec{v_1}=

\displaystyle \vec{v_2}=

The sum of both vectors can be done by adding individually its components

\displaystyle \vec{v_1}+\vec{v_2}=

If the vectors are given as a magnitude and an angle (M\ ,\ \theta ), each component can be found as

\displaystyle \vec{v_1}=

\displaystyle \vec{v_2}=

The first vector has a magnitude of 3.14 m and an angle of 30°, so

\displaystyle \vec{v_1}=

\displaystyle \vec{v_1}=

The second vector has a magnitude of 2.71 m and an angle of -60°, so

\displaystyle \vec{v_2}=

\displaystyle \vec{v_2}=

The sum of the vectors is

\displaystyle \vec{v_1}+\vec{v_2}=

\displaystyle \vec{v_1}-\vec{v_2}=

Finally, we compute the magnitude of the sum

\displaystyle |\vec{v_1}+\vec{v_2}|=\sqrt{(4.08)^2+(-0.78)^2}

\displaystyle |\vec{v_1}+\vec{v_2}|=\sqrt{17.25}

\displaystyle |\vec{v_1}+\vec{v_2}|=4.15m

3 0
2 years ago
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