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Shalnov [3]
4 years ago
11

A 1 m wide continuous footing is designed to support an axial column load of 250 kN per meter of wall length. The footing is pla

ced 0.5 m into a soil with a cohesion of 25 kPa and an angle of internal friction of 5°. Most nearly, what is the value of the Terzaghi bearing capacity factor, N?(A) 0.5(B) 1.1(C) 1.6(D) 7.3
Engineering
1 answer:
creativ13 [48]4 years ago
7 0

Answer:

correct option is (A) 0.5

Explanation:

given data

axial column load = 250 kN per meter

footing placed =  0.5 m

cohesion = 25 kPa

internal friction angle =  5°

solution

we know angle of internal friction is 5° that is near to 0°

so it means the soil is almost cohesive soil.

and for  a pure cohesive soil

N_{\gamma } = 0

and we know formula for N_{\gamma } is

N_{\gamma } = (Nq - 1 ) × tan(Ф)   ..................1

so here Ф is very less  N_{\gamma } should be nearest to zero

and its value can be 0.5

so correct option is (A) 0.5

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egoroff_w [7]

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For this question, the difference between a point on the circumference and a point on the axis will be:

p_{B} - p_{A} = \frac{p_{fluid}.w^{2}.r_{B} ^{2} }{2} - γfluid.z_{B} - (\frac{p_{fluid}.w^{2}.r_{A} ^{2} }{2} - γfluid.z_{A})

p_{B} - p_{A} = \frac{p_{fluid}.w^{2}}{2} (r_B^{2} - r_A^{2} ) - γfluid(z_{B} -z_{A})

Since there is no variation in the z-axis, z = 0 and that the density of oil is 0.9.10³kg/m³:

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8 0
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A parallel circuit with two branches and an 18 volt battery. Resistor #1 on the first branch has a value of 220 ohms and resisto
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