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Shalnov [3]
4 years ago
11

A 1 m wide continuous footing is designed to support an axial column load of 250 kN per meter of wall length. The footing is pla

ced 0.5 m into a soil with a cohesion of 25 kPa and an angle of internal friction of 5°. Most nearly, what is the value of the Terzaghi bearing capacity factor, N?(A) 0.5(B) 1.1(C) 1.6(D) 7.3
Engineering
1 answer:
creativ13 [48]4 years ago
7 0

Answer:

correct option is (A) 0.5

Explanation:

given data

axial column load = 250 kN per meter

footing placed =  0.5 m

cohesion = 25 kPa

internal friction angle =  5°

solution

we know angle of internal friction is 5° that is near to 0°

so it means the soil is almost cohesive soil.

and for  a pure cohesive soil

N_{\gamma } = 0

and we know formula for N_{\gamma } is

N_{\gamma } = (Nq - 1 ) × tan(Ф)   ..................1

so here Ф is very less  N_{\gamma } should be nearest to zero

and its value can be 0.5

so correct option is (A) 0.5

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Explanation:

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A. Name the major strengthening mechanisms in metals and explain the working principle under each mechanism.Give the relevant eq
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a) Solid solution strengthening and alloying,  Precipitation hardening, work hardening

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Explanation:

<u>A) strengthening mechanism</u>

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In solid solution strengthening and alloying mechanism there is an addition of one atom of solute to another during this process, there might be substitution of interstitial point defect in crystal

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Consider a junction that connects three pipes A, B and C. What can we say about the mass flow rates in each pipe for steady flow
Elis [28]

Answer:

The statement regarding the mass rate of flow is mathematically represented as follows \Rightarrow \rho \times Q_{3}=\rho \times Q_{1}+\rho \times Q_{2}

Explanation:

A junction of 3 pipes with indicated mass rates of flow is indicated in the attached figure

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\rho =\frac{mass}{Volume}

Using the above relations in our basic equation of continuity we obtain

\rho \times V_{3}=\rho \times V_{1}+\rho \times V_{2}\\\\Q_{3}\times t=Q_{1}\times t+Q_{2}\times t\\\\\Rightarrow Q_{3}=Q_{1}+Q_{2}

Thus the mass flow rate equation becomes \Rightarrow \rho \times Q_{3}=\rho \times Q_{1}+\rho \times Q_{2}

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