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Oduvanchick [21]
3 years ago
10

How do we need to prepare for the future?

Engineering
1 answer:
Paraphin [41]3 years ago
5 0
B. to achieve sustainable development
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The highest cutting temperature is located close to the shear zone. a) True b) False
Minchanka [31]

Answer:

a)True

Explanation:

In cutting action,three type of zone are presents

1.Primary zone :

The most of part of energy is converted in to heat.

2.Secondary zone:

Heat generation due to rubbing between tool and chip.This also called deformation zone.

3.Tertiary zone:

Heat generated due to flank of tool and already machined surface.

So the highest temperature is located close to the shear zone.

7 0
3 years ago
Modify the sentence-generator program so that it inputs its vocabulary from a set of text files at startup. The filenames are no
OlgaM077 [116]

Answer:

1

Explanation:

3 0
1 year ago
What is the meaning of 52k?
amm1812

Answer:

52K is a form of money or amount. It basically means 52,000.

Explanation:

K stands for thousand.

4 0
2 years ago
Glucose can be broken down to two 3-carbon compound called___and related energy called___
rusak2 [61]

Glucose can be broken down to two 3-carbon compound called pyruvate and related energy called ATP

4 0
3 years ago
The lattice parameter of copper is 0.362 nanometer. The atomic weight of copper is 63.54 g/mole. Copper forms a fcc structure. A
Hatshy [7]

Answer:

a) 4.74 * 10^-23 cm^3

b)  8.9 g/cm^3

Explanation:

Given data :

Lattice parameter of copper = 0.362 nM

Atomic weight of copper = 63.54 g/mole

Given that copper forms a fcc structure

<u>a) Calculate the volume of the unit cell</u>

V = a^3

  = ( 0.362 * 10^-7  cm )^3 = 4.74 * 10^-23 cm^3

<u>b) Calculate density of copper in g/cm^3 </u>

Density = ( n*A ) / ( Vc * NA) ----------- ( 1 )

where: NA = Avogadro's number = 6.022 * 10^23  atoms/mol

n = number of atoms per unit cell = 4

A = atomic weight = 63.54 g/mol

Vc = volume of unit cell =  4.74 * 10^-23 cm^3

Input values into equation 1

Density = 8.9 g/cm^3

3 0
3 years ago
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