Question

Three pumpkins are catapulted at a contest. How much farther does Pumpkin C travel than Pumpkin A? • Pumpkin A travels 0.61 mile. • Pumpkin B travels 0.28 mile farther than Pumpkin A. • Pumpkin B travels 0.06 mile farther than Pumpkin C.

Answer 1

Answer:

0.22 miles

Step-by-step explanation:

Let

A = Distance pumpkin A travels = 0.61 miles

Distance pumpkin B travels is 0.28 mile farther than Pumpkin A

$B=0.28+A\\\Rightarrow B=0.28+0.61\\\Rightarrow B=0.89\ \text{miles}$

Distance pumpkin B travels is 0.06 miles further than pumpkin C

$B=0.06+C\\\Rightarrow C=B-0.06\\\Rightarrow C=0.89-0.06\\\Rightarrow C=0.83\ \text{miles}$

To calculate how much farther pumpkin C travels than pumpkin A we have the subtract their distances

$C-A=0.83-0.61=0.22\ \text{miles}$

So, pumpkin C traveled 0.22 miles more than pumpkin A.