1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Softa [21]
3 years ago
14

An element has the mass number 12 and atomic number 6. The number of neutron in it is?

Chemistry
1 answer:
slamgirl [31]3 years ago
8 0

Answer:

12-6=6

the answer is A)6

You might be interested in
Can someone please explain core and valence electrons in periods for me please​
Lena [83]

Answer:

The electrons of an atom are typically divided into two categories: valence and core electrons. Valence electrons occupy the outermost shell or highest energy level of an atom while core electrons are those occupying the innermost shell or lowest energy levels

Explanation:

i hope u get it :))

6 0
3 years ago
What’s the answer plz help quick ?????
UNO [17]

Your independent variable would be salt because it doesn't change the only thing that changes is the water.

7 0
3 years ago
Anyone know a simple way to describe friction not the definition online, just what you think
Schach [20]

Answer:

the resistance that one surface or object encounters when moving over another.

Explanation: :D

4 0
3 years ago
Read 2 more answers
The solubility of the ionic compound MX3, having a molar mass of 288 g/mol, is 3.60 x 10-2 g/L. Calculate the KSP of the compoun
GarryVolchara [31]

K_{sp} of the compound is found to be  5.04 ×10^{-10}.

Solubility :Solubility can be define as the amount of a substance that dissolves or mixes in a given amount of solvent at specific conditions.

Solubility equilibrium

Ksp = [A^{+} ]^{a} [B^{-} ]^{b}

Ksp = solubility product constant

A+ = cation in an aquious solution

B- = anion in an aqueous solution

a, b = relative concentrations of a and b

Given,

Solubility = s = 3.60 × 10^{-2} g/L

molar mass = 288 g/ mol

∴ s= 3.60 × 10^{-2} g/L ÷ 288 g/ mol = 1.25 ×10^{-4} mol/ L

Reaction:

MX3 ⇄ M + 3X

           s       3s

K_{sp} =[ M^{+3}] [ X^{-1}]^{3} = solubility product

∴ K_{sp} =[s]^{} [3s]^{3}

∴ K_{sp} = 3 s^{4}

∴ K_{sp} = 3 × (3.60 × 10^{-2} )^{4}

∴ K_{sp} = 503.8848 ×10^{-8}  = 5.04 ×10^{-10}

Learn more about solubility here .....

brainly.com/question/23946616

#SPJ1

7 0
2 years ago
If 0.138g of cyclohexene (c6h10) was obtained from 0.240g of cyclohexanol (c6h120), what is the percentage yield of cyclohexene?
tino4ka555 [31]
<span>Given in the question- 1 mole of cyclohexanol = > 1 mole of cyclohexene Molar mass 100.16 g/mol moles of cyclohexanol = .240 / 100.16= 0.002396 moles Molar mass 82.143 g/mol moles of cyclohexene formed @100 % yield = 0.002396 Molar mass 82.143 g/mol mass of cyclohexene @ 100 % = .002396 x 82.143 = 0.197g bur we have .138g so % yield = .138 / .197 = 70.0 % Ans- 70 percentage yield of cyclohexene.</span>
4 0
3 years ago
Other questions:
  • In the reaction Pb + Cu2+ → Pb2+ + Cu, the Cu2+
    9·1 answer
  • Which way of dissolving changes the chemical identity of the solute?
    6·2 answers
  • Which of the following data tables correctly shows how temperature affects the reaction between sodium thiosulfate and hydrochlo
    9·2 answers
  • What type of intermolecular force contributes to the high boiling point of water??
    15·2 answers
  • CAM SOMEONE PLEASE HELP MW WITH THIS I WILL BRAINLIEST WHO EVER TELLS ME THE ANSWERS TO THIS
    13·1 answer
  • L 1.1.4 Quiz: Calculating Heat
    11·1 answer
  • Find the number of molecules in 35.20 g of nitrogen dioxide
    15·2 answers
  • If Phosphorus, P, gained 3 electrons, the net ion charge would be<br><br> +5<br> -5<br> +3<br> -3
    14·1 answer
  • What are the key differences between solutions and mechanical mixtures? Give two examples of each. -Science
    14·1 answer
  • 16. Ramps, wedges, and chisels are examples of what type of machines?
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!