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<u>Answer:</u> The value of for given reaction is 0.465
<u>Explanation:</u>
We are given:
Initial concentration of A = 0.650 M
Initial concentration of B = 1.35 M
Initial concentration of C = 0.300 M
Equilibrium concentration of A = 0.550 M
Equilibrium concentration of B = 0.400 M
For the given chemical equation:
<u>Initial:</u> 0.65 1.35 0.30
<u>At eqllm:</u> 0.65-x 1.35-2x 0.30+x
Evaluating the value of 'x'
So, equilibrium concentration of B = 1.35 - 2x = [1.35 - 2(0.100)] = 1.15 M
Equilibrium concentration of C = (0.30 + x) = (0.300 + 0.100) = 0.400 M
The expression of for above equation follows:
Putting values in above equation, we get:
Hence, the value of for given reaction is 0.465