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3 years ago

CAN SOMEONE HELP ME OUT WITH THIS PLEASE AND THINK YOU

Mathematics

2 answers:

Alexus [3.1K]3 years ago

7 0

The answer is 10 7/10

m_a_m_a [10]3 years ago

6 0

Answer:

$10\frac{7}{18}$

Step-by-step explanation:

First revert it to improper fraction.

$\frac{13}{2} +\frac{35}{9} \\\\$

Now put them to a common denominator.

$\frac{187}{18}$

=> $10\frac{7}{18}$

You might be interested in

A restaurant makes pizzas with 6-inch diameters ad 12-inch diameters. Which of the following statement is true?

a_sh-v [17]

Answer:

The correct option is c: the area of the 6-inch pizza is 1/4 the area of the 12-inch pizza.

Step-by-step explanation:

The area (A) of each pizza is given by:

$A = \pi r^{2}$

Where:

r: is the radius

For the 12-inch pizza we have:

$A_{12} = \pi (\frac{12 inch}{2})^{2} = 113.1 inch$

And for the 6-inch pizza we have:

$A_{6} = \pi (\frac{6 inch}{2})^{2} = 28.3 inch$

The ratio between A₆ and A₁₂ is:

$\frac{A_{6}}{A_{12}} = \frac{28.3 inch}{113.1 inch} = 0.25 = \frac{1}{4}$

Hence:

$A_{6} = \frac{A_{12}}{4}$

Therefore, the correct option is c: the area of the 6-inch pizza is 1/4 the area of the 12-inch pizza.

I hope it helps you!

4 0

3 years ago

What value of a makes the equation true?

zimovet [89]

The answer is A heheue

5 0

3 years ago

a toy store marks down every toy by 15% in January. How much does a toy cost during January? Use p for the price in December.

satela [25.4K]

A toy cost 0.85p in January.

Step-by-step explanation:

Given,

Mark down in January = 15%

Let,

Price in December = p

Mark down in January = 15% of price in December

Mark down in January = $\frac{15}{100}*p$

Mark down in January = 0.15p

Price of toy in January = Price in December - Mark down

Price of toy in January = p - 0.15p = 0.85p

A toy cost 0.85p in January.

Keywords: mark down, subtraction

Learn more about subtraction at:

#LearnwithBrainly

7 0

3 years ago

The table shows a linear relationship between x and y

irga5000 [103]

We have been given a table that shows a linear relationship between x and y. We are asked to find the rate of change change of y with respect to x.

To solve our given problem, we will find the slope of the line passing through the given points.

$m=\frac{y_2-y_1}{x_2-x_1}$

Let us find slope of line using points $(-20,96)$ and $(-2,15)$ .

$m=\frac{15-96}{-2-(-20)}$

$m=\frac{-81}{-2+20}$

$m=\frac{-81}{18}$

$m=-4.5$

Therefore, the rate of change of y with respect to x is $-4.5$ .

3 0

3 years ago

Suppose ABC is a right triangle with sides a, b, and c and right angle at C. Find the unknown side length using the Pythagorean

Leno4ka [110]

Answer:

a = $\sqrt{7}$

Step-by-step explanation:

I think your question is missed of key information, allow me to add in and hope it will fit the original one.:

<em>Suppose ABC is a right triangle with sides a, b, and c and right angle at C. Find the unknown side length using the Pythagorean theorem and then find the values of the six trigonometric functions for angle B. when b=3 and c=4</em>.

My answer:

We will Pythagoras theorem, which states that the sum of squares of two legs of a right triangle is equal to the square of the hypotenuse of right triangle. Because the question says that ABC is a right triangle.

$a^2+b^2=c^2$

Given that: b=3 and c=4

$a^2+3^2=4^2a^2+9=16a^2+9-9=16-9a^2=7$

so a = $\sqrt{7}$

We know that tangent relates opposite side of a right triangle with adjacent side.

$\text{tan}(B)=\frac{a}{b}\\\text{tan}(B)=\frac{\sqrt{7}}{3}$

Please have a look at the attached photos.

3 0

4 years ago