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klasskru [66]
3 years ago
10

A sound wave can cause the particles in a medium to vibrate slowly or quickly what is this rate of vibration called?

Physics
2 answers:
larisa [96]3 years ago
5 0

Answer: C:frequency

the rate of the vibration is called frequency

stealth61 [152]3 years ago
3 0

Answer:

FREQUENCY

Explanation:

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Write a hypothesis about the use of an object’s physical characteristics to determine its density. Use the format "if . . . then
Ad libitum [116K]

Answer:

If an object has a high density then the molicules making up that object are closly packed togeather. Because of this, objects with a higher density will have more mass than objects of the same size that have a lesser density.

7 0
3 years ago
A softball player moving 3.89 m/s
Ahat [919]

Answer:

0.119 s

Explanation:

Given that

U=3.89\ m/s\\a=-1.44\ m/s^2\\S=4.8\ m

Lets take final speed of the softball after covering 4.8 m = V

We know that

V^2=U^2+2aS\\V^2=3.89^2-2\times 1.44\times 4.8\\V=3.7\ m/s

Also We know that

V=U+at\\

Putting the value of V ,U and a in the previous equation  We get

3.7=3.89-1.44\times t\\t=0.119\ s

Therefore slide time will be 0.119 s

3 0
3 years ago
What is the formula of a compound formed between strontium (Sr) and chlorine (Cl)? (2 points)
Sidana [21]
The chemical formula of the compound of strontium and chlorine would be SrCl2. It is a salt of the strontium ion and chloride ion and a white crystalline compound. When burned, it produces a bright red hue. That is why it found some application in fireworks.  
 Read more on Brainly - brainly.com/sf/question/4154091
8 0
3 years ago
A kangaroo has a maximum gravitational potential energy during one jump of 770 J
KengaRu [80]

Answer:

k = 44000 N/m

Explanation:

Given the following data;

Maximum gravitational potential energy = 770 J

Elastic potential energy = 14% of 770 J = 14/100 * 770 = 107.8 J

Extension, x = 42 - 35 = 7cm to meters = 7/100 = 0.07 m

To find the spring constant, k;

The elastic potential energy of an object is given by the formula;

E.P.E = \frac {1}{2}kx^{2}

Substituting into the equation, we have;

107.8 = \frac {1}{2}*k*0.07^{2}

107.8 = \frac {1}{2}*k*0.0049

Cross-multiplying, we have;

215.6 = k*0.0049

k = \frac {215.6}{0.0049}

k = 44000 N/m

5 0
3 years ago
An Airplane taxis onto the runway going at 10 m/s. If it can accelerate steady at 3
kirza4 [7]

Answer: 1333 m

the length of runway it will need is S = \frac{90^{2}-10^{2}  }{2.3}=1333 (m)

Explanation:

4 0
3 years ago
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