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n200080 [17]
3 years ago
15

Which of the following best describe a generator?

Physics
1 answer:
sukhopar [10]3 years ago
5 0

c because a generator generates electricity with the use of another energy source like nuclear,solar,wind,fossil fuel,gasoline or in rare cases temperature

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For an object on a flat surface, the force of gravity is 15 newtons downward and the normal force is 15 newtons upward. The appl
fgiga [73]

Answer:

There is a net force of 2 N to the left.

With 8 N to the left the up/down and left/right forces are in balance.

The force left over is 2 N to the left.

5 0
2 years ago
The system is released from rest at θ = 0° when a constant couple moment M = 100 N.m is applied. If the mass of the cable and li
Fantom [35]

For a system released from rest at θ = 0° when a constant couple moment M = 100 N.m is applied,  the speed of the 10-kg block is mathematically given as

V=4.33m/s

<h3>What is the speed of the 10-kg block?</h3>

Generally, the equation for the workdone  is mathematically given as

W=T tehta<dtheta

W=100(90*\pi/180)

W=1.5707*100

W=1.57Nm

The change in potential energy across the pulley

dP=mgh

dp=10*9.81*111.8

dp=10.97J

For the thrid position, potential energy is

dP=mg(0.3)

dP=17.658J

dP'=17.658J-13.125

dP'=-4.532J

For 2nd position dP=0

The change in Kinectic energy across the pulley\

dK.E=0.5mv^2

For 1st

dk.E=0.5m(10)^2

2nd

dK.E=0.5Iw^2

dK.E=0.5(7.5*10^-3)(v^2/0.05)^2

3rd

2nd=3rd

In conclusion,

157.07=dKE+dP.E

157.07=5v^2+ (7.5*10^-3)(v^2/0.05)^2+10.97-4.53

V=4.33m/s

Read more about Kinetic energy

brainly.com/question/999862

4 0
2 years ago
Which of Jafar's statements are correct regarding distance and displacement?
shepuryov [24]

Answer:The distance and magnitude of displacement are sometimes equal." Jafar is correct. The distance traveled and the magnitude of displacement are equal if and only if the path is a straight line in one direction.

Explanation:

5 0
3 years ago
A deep space probe travels in a straight line at a constant speed of over 16,000 m/s. Assuming there is no friction in space, if
77julia77 [94]
C because when the part gets out of the probe it would no longer stay contacted
6 0
3 years ago
A BMX bicycle rider takes off from a ramp at a point 2.4 m above the ground. The ramp is angled at 40 degrees from the horizonta
adoni [48]

Answer:

The BMX lands 5.4 m from the end of the ramp.

Explanation:

Hi there!

The position of the BMX is given by the position vector "r":

r = (x0 + v0 · t · cos α, y0 + v0 · t · sin α + 1/2 · g · t²)

Where:

r = position vector at time t

x0 = initial horizontal position

v0 = initial velocity

α = jumping angle

y0 = initial vertical position

g = acceleration due to gravity (-9.8 m/s² considering the upward direction as positive)

Please, see the attached graphic for a better understanding of the situation. At final time, when the bicycle reaches the ground, the vector position will be "r final" (see figure). The y-component of the vector "r final" is - 2.4 m (placing the origin of the frame of reference at the jumping point). With that information, we can use the equation of the y-component of the vector "r" (see above) to calculate the time of flight. With that time, we can then obtain the x-component (rx in the figure) of the vector "r final". Then:

y = y0 + v0 · t · sin α + 1/2 · g · t²

-2.4 m = 0 m + 5.9 m/s · t · sin 40° - 1/2 · 9.8 m/s² · t²

0 = -4.9 m/s² · t² + 5.9 m/s · t · sin 40° + 2.4 m

Solving the quadratic equation:

t = 1.2 s

Now, we can calculate the x-component of the vector "r final" that is the horizontal distance traveled by the bicycle:

x = x0 + v0 · t · cos α

x = 0 m + 5.9 m/s · 1.2 s · cos 40°

x = 5.4 m

The BMX lands 5.4 m from the end of the ramp.

Have a nice day!

8 0
3 years ago
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