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Hatshy [7]
3 years ago
7

Suzie skydiver, who weighs 500 n, reaches terminal velocity of 90 km/h. the air resistance on suzie is then

Physics
2 answers:
Gekata [30.6K]3 years ago
8 0

Answer: Air resistance would be 625Newton

Explanation: For small object the air resistance is directly proportional to the velocity that is if you triple the Velocity the air resistance is also tripled.

But for large object like ball and human the air resistance is proportional to the square of the Velocity that is V². So in this case the velocity given is 90km/h which is also 25 m/s.

So the air resistance on Suzie would be the square of the Velocity which is 25² = 625N

masha68 [24]3 years ago
7 0
<span>Weight of the skydiver m = 500 N
 Terminal velocity V = 90 km/h
 Here the weight of the person acts as the force, so based on the Newton's third law the applied is the force what we but in the opposite direction making the resistance. So the air resistance exerted on Suzie will be her weight that is 500N</span>
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3 years ago
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Misha Larkins [42]

Hi there!

The maximum deformation of the bumper will occur when the car is temporarily at rest after the collision. We can use the work-energy theorem to solve.

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KE = \frac{1}{2}mv^2

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v = velocity (14.6 m/s)

Once the car is at rest and the bumper is deformed to the maximum, we only have spring-potential energy:

U_s = \frac{1}{2}kx^2

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Since energy is conserved:

E_I = E_f\\\\KE = U_s\\\\\frac{1}{2}mv^2 = \frac{1}{2}kx^2

We can simplify and solve for 'x'.

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