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statuscvo [17]
3 years ago
9

A particle R moves with a velocity of 6 m/s due East and another particle S moves at 8 m/s due South. What is the magnitude of t

he velocity of R w.r.t S?
Physics
1 answer:
cluponka [151]3 years ago
6 0

Answer:

10

Explanation:

We can look at this problem as a triangle, r is the hypotenuse so if we take the square root of 6^2+8^2 we get 10

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Question 10 of 10
Margaret [11]

Answer: D. 5.0(10)^{-38} J

Explanation:

The energy E of an electromagmetic wave is given by:

E=\frac{hc}{\lambda}

Where:

h=6.626(10)^{-34}J.s is the Planck constant

c=3(10)^{8} m/s is the speed of light in vacuum

Then hc=1.99 (10)^{-25}Jm

\lambda=4.0(10)^{12} m is the wavelength

Solving:

E=\frac{1.99 (10)^{-25}Jm}{4.0(10)^{12} m}

E=5.0(10)^{-38} J

7 0
3 years ago
Why is there a universe at all
Soloha48 [4]

Answer:GOD ;)

Explanation:

6 0
3 years ago
While skydiving, your parachute opens and you slow from 50.0 m/s to 8.0 m/s in 0.75 s . Determine the distance you fall while th
Anestetic [448]

Answer:

21.75 m

Explanation:

t = Time taken for the car to slow down = 0.75 s

u = Initial velocity = 50 m/s

v = Final velocity = 8 m/s

s = Displacement

a = Acceleration

Equation of motion

v=u+at\\\Rightarrow a=\frac{v-u}{t}\\\Rightarrow a=\frac{8-50}{0.75}\\\Rightarrow a=-56\ m/s^2

Acceleration is -56 m/s²

v^2-u^2=2as\\\Rightarrow s=\frac{v^2-u^2}{2a}\\\Rightarrow s=\frac{8^2-50^2}{2\times -56}\\\Rightarrow s=21.75\ m

The distance covered in the 0.75 seconds is 21.75 m

8 0
3 years ago
Unmoving objects are being acted on by balance forces. TRUE or FALSE?
Reil [10]
True. There are forced acting on it, but as they're balanced it is unmoving
3 0
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Answer:

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