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statuscvo [17]
3 years ago
9

A particle R moves with a velocity of 6 m/s due East and another particle S moves at 8 m/s due South. What is the magnitude of t

he velocity of R w.r.t S?
Physics
1 answer:
cluponka [151]3 years ago
6 0

Answer:

10

Explanation:

We can look at this problem as a triangle, r is the hypotenuse so if we take the square root of 6^2+8^2 we get 10

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Answer:

\displaystyle \vec{d}=

Explanation:

<u>Displacement Vector</u>

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\displaystyle P_1(x_1,y_1)

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The question describes the situation where the initial point is the base of the mountain, where both components are zero

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\displaystyle \vec{d}=

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