The amount of energy that a wave may transfer to a unit area of a surface each second is measured as the wave's intensity. Watts per square meter is a unit used to express intensity. A sound wave's frequency is equal to its rate of vibration, and its intensity is determined by its amplitude.
<h3>What is the intensity of sound waves affect the frequency?</h3>
The energy of a vibration is quantified in decibels as intensity or loudness (dB). A sound has a high intensity if it is loud.
Therefore, perceive noise as louder the higher the frequency, although frequency does not indicate how loud a sound is.
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Answer:
<em>The frequency changes by a factor of 0.27.</em>
<em></em>
Explanation:
The frequency of an object with mass m attached to a spring is given as
= 
where is the frequency
k is the spring constant of the spring
m is the mass of the substance on the spring.
If the mass of the system is increased by 14 means the new frequency becomes
= 
simplifying, we have
= 
= 
if we divide this final frequency by the original frequency, we'll have
==> ÷
==> x 
==> 1/3.742 = <em>0.27</em>
Answer: True!
Explanation: The force is proportional to the square of the distance between 2 point masses
Answer:
La masa de la mascota es de 11,24 kg.
Explanation:
Dado que la masa total de = 80 kg
Tenemos
Fuerza de fricción = 80 kg × 9.81 × 0.3 = 235.44 N
La mascota salta horizontalmente con una velocidad, v, de 6.0 m / s para dar un movimiento de 1 m a la caja de masa y a la persona
Trabajo realizado por el salto de la mascota = (80 - m) × 9.81 × 0.3
La energía del movimiento del perro = 1/2 × m × v² = Trabajo realizado al saltar de la mascota
1/2 × m × 6² = (80 - m) × 9.81 × 0.3
20943 · m = 235440
m = 235440/20943 = 11,24 kg
