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stepladder [879]
3 years ago
7

How much 6.0 M of nitrous acid (HNO2), in milliliters, is needed to make 235 mL of 1.00M HNO2?

Chemistry
1 answer:
vladimir1956 [14]3 years ago
3 0

Answer:

How many hydrogen MOLECULES are needed to produce 2 molecules of water (H2O)?

Explanation:

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The metal content of iron in ores can be determined by a redox procedure in which the sample is first oxidized with Br2 to conve
coldgirl [10]

Answer:

80.27%

Explanation:

Let's consider the following balanced equation.

2 Fe³⁺(aq) + Sn²⁺(aq) ⇒ 2Fe²⁺(aq) + Sn⁴⁺(aq)

First, we have to calculate the moles of Sn²⁺ that react.

\frac{0.1015molSn^{2+} }{1L} .13.28 \times 10^{-3} L=1.348\times 10^{-3}molSn^{2+}

We also know the following relations:

  • According to the balanced equation, 1 mole of Sn²⁺ reacts with 2 moles of Fe³⁺.
  • 1 mole of Fe³⁺ is oxidized from 1 mole of Fe.
  • The molar mass of Fe is 55.84 g/mol.

Then, for 1.348 × 10⁻3 moles of Sn²⁺:

1.348\times 10^{-3}molSn^{2+}.\frac{2molFe^{3+} }{1molSn^{2+} } .\frac{1molFe}{1molFe^{3+} } .\frac{55.84gFe}{1molFe} =0.1505gFe

If there are 0.1505 g of Fe in a 0.1875 g sample, the mass percentage of Fe is:

\frac{0.1505g}{0.1875g} \times 100 \% = 80.27\%

5 0
3 years ago
A 2.50 g sample of solid sodium hydroxide is added to 55.0 mL of 25 °C water in a foam cup (insulated from the environment) and
zlopas [31]

Answer:

37.1°C.

Explanation:

  • Firstly, we need to calculate the amount of heat (Q) released through this reaction:

<em>∵ ΔHsoln = Q/n</em>

no. of moles (n) of NaOH = mass/molar mass = (2.5 g)/(40 g/mol) = 0.0625 mol.

<em>The negative sign of ΔHsoln indicates that the reaction is exothermic.</em>

∴ Q = (n)(ΔHsoln) = (0.0625 mol)(44.51 kJ/mol) = 2.78 kJ.

  • We can use the relation:

Q = m.c.ΔT,

where, Q is the amount of heat released to water (Q = 2781.87 J).

m is the mass of water (m = 55.0 g, suppose density of water = 1.0 g/mL).

c is the specific heat capacity of water (c = 4.18 J/g.°C).

ΔT is the difference in T (ΔT = final temperature - initial temperature = final temperature - 25°C).

∴ (2781.87 J) = (55.0 g)(4.18 J/g.°C)(final temperature - 25°C)

∴ (final temperature - 25°C) = (2781.87 J)/(55.0 g)(4.18 J/g.°C) = 12.1.

<em>∴ final temperature = 25°C + 12.1 = 37.1°C.</em>

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antiseptic1488 [7]
The molar mass for PCL3 is 137.33 g/mol
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