Answer:
A. Yes, Amanda find the number of moles of NaCl correctly.
B. 0.73 M.
Explanation:
<em>A. Did Amanda find the number of moles of NaCl correctly? If not, explain.
</em>
-
Yes, Amanda find the number of moles of NaCl correctly.
- The relation to find the no. of moles of NaCl is:
<em>No. of moles (n) of NaCl = mass/molar mass.</em>
mass of NaCl = 32.0 g, molar mass of NaCl = 58.45 g/mol.
∴ No. of moles (n) of NaCl = mass/molar mass = (32.0 g)/(58.45 g/mol) = (32.0 g NaCl)*(1 mol of NaCl)/(58.45 g NaCl) = 0.547 mol ≅ 0.55 mol.
<em>B. What does Amanda need to do next to calculate the molarity of the NaCl solution? Show your work for full credit.</em>
<em></em>
- Molarity is the no. of moles of solute dissolved in a 1.0 liter of a solution.
∴ M = (no. of moles of NaCl)/(volume of solution (L)) = (0.55 mol)/(0.75 L) = 0.73 M.
The quantity of electricity : 2 Faraday = 193000 Coulomb
<h3>Further explanation</h3>
Given
2 moles of electrons
Required
The quantity of electricity
Solution
According to Faraday, the amount of current flowing in the electrolysis cell is closely related to the amount of substance that reacts
1 Faraday is the amount of electricity that is passed in the electrolysis cell to obtain 1 mole of electrons. 1 mole of electrons is equivalent to an electric charge of 96500 Coulombs.
The conversion / relationship can be stated as follows:
1 Faraday = 1 mole of electrons = 96500 Coulombs
1 faraday = coulomb / 96500
Can be formulated
Coulomb = Q = I. t so:
so for 2 moles electrons :
= 2 x 96500 C
= 193000 C
= 2 Faraday
Answer:
0.924 g
Explanation:
The following data were obtained from the question:
Volume of CO2 at RTP = 0.50 dm³
Mass of CO2 =?
Next, we shall determine the number of mole of CO2 that occupied 0.50 dm³ at RTP (room temperature and pressure). This can be obtained as follow:
1 mole of gas = 24 dm³ at RTP
Thus,
1 mole of CO2 occupies 24 dm³ at RTP.
Therefore, Xmol of CO2 will occupy 0.50 dm³ at RTP i.e
Xmol of CO2 = 0.5 /24
Xmol of CO2 = 0.021 mole
Thus, 0.021 mole of CO2 occupied 0.5 dm³ at RTP.
Finally, we shall determine the mass of CO2 as follow:
Mole of CO2 = 0.021 mole
Molar mass of CO2 = 12 + (2×16) = 13 + 32 = 44 g/mol
Mass of CO2 =?
Mole = mass /Molar mass
0.021 = mass of CO2 /44
Cross multiply
Mass of CO2 = 0.021 × 44
Mass of CO2 = 0.924 g.
Six !
Just count each element in the molecule (Since there are 4 hydrogen atoms, a carbon and an oxygen atom in this molecule of methanol.)
The red sign pops up on the side of the bus.
