Answer:
Liquids in a form of mixture has less weight as compared to sum of all liquid's weight due to release of gases.
The combined weights of several liquids mixed in an open flask be less than the sum of all the weights of the liquids because when the reaction occurs new products are formed and also some gases which releases in the atmosphere.
These gases also contribute in the weight of the product so when it is released the weight of the mixture of liquids are less than the sum of the weights of all liquids so we can conclude that liquids in a form of mixture has less weight as compared to sum of all liquid's weight.
Explanation:
By looking at it and if it is making a single movement it is moving.
Answer:
I know that the 100-mL graduated cylinders are always read to 1 decimal place.
I think for 50 mL graduated cylinders, it lets you measure volumes up to 50.0 mL to the nearest 0.1 or 0.2 mL, depending on your exact cylinder.
Answer:
Option C = 30 j
Explanation:
Given data:
mass of snowboard = 5 Kg
Initial speed = 2 m/s
final speed = 4 m/s
work done = ΔE= ?
ΔE= change in kinetic energy
Solution:
Formula:
K.E (initial) = 1/2 × mv²
K.E (initial) = 1/2 × 5 Kg . (2m/s)²
K.E (initial) = 1/2 × 20 Kg.m²/s²
K.E (initial) = 10 Kg.m²/s² or 10 J
Kg.m²/s² = J
K.E (finial) = 1/2 × mv²
K.E (finial) = 1/2 × 5 Kg . (4m/s)²
K.E (finial) = 1/2 × 5 Kg . 16 m²/s²
K.E (finial) = 1/2 × 80 Kg.m²/s²
K.E (finial) = 40 Kg.m²/s² or 40 J
work done = ΔE = K.E (finial) - K.E (initial)
work done = ΔE = 40 J - 10 J
work done = ΔE = 30 J
Answer:
3.94 × 10³ g
Explanation:
Step 1: Write the neutralization reaction
HClO₃ + NaOH = NaClO₃ + H₂O
Step 2: Calculate the moles of chloric acid that react
25.5 L of 3.86 M chloric acid is to be neutralized. The reacting moles are:
Step 3: Calculate the required moles of sodium hydroxide
The molar ratio of HClO₃ to NaOH is 1:1. Then, the reacting moles of NaOH are 98.4 moles.
Step 4: Calculate the mass of sodium hydroxide corresponding to 98.4 moles
The molar mass of NaOH is 40.00 g/mol.
