P1/T1=P2/T2 Gal Lussac's Law
25 C= 298K (just add 273)
0 C= 273 k
6.00atm/298=P2/273
P2=5.50 atm
Explanation:
The pH of a solution can you be found by using the formula
![pH = - log [ { H_3O}^{+}]](https://tex.z-dn.net/?f=pH%20%3D%20-%20log%20%5B%20%7B%20H_3O%7D%5E%7B%2B%7D%5D)
Since we are finding the [H3O+] , substitute the value of the pH and find it's antilog
We have
![4.63 = - log[ { H_3O}^{+}] \\ [ { H_3O}^{+}] = {10}^{ - 4.63} \\ \\ = 2.344 \times {10}^{ - 5} mol {dm}^{ - 3}](https://tex.z-dn.net/?f=4.63%20%3D%20%20-%20%20log%5B%20%7B%20H_3O%7D%5E%7B%2B%7D%5D%20%5C%5C%20%5B%20%7B%20H_3O%7D%5E%7B%2B%7D%5D%20%20%20%3D%20%20%7B10%7D%5E%7B%20-%204.63%7D%20%20%5C%5C%20%20%20%5C%5C%20%20%3D%202.344%20%5Ctimes%20%20%7B10%7D%5E%7B%20-%205%7D%20mol%20%7Bdm%7D%5E%7B%20-%203%7D%20%20)
Hope this helps you
Answer:
1)
Explanation:
Fe+2 + 2e -> Fe
The element that is reduced gains electrons. In this case Fe is gaining electrons
Answer:
4–ethyl–2,3–dimethylheptane
Explanation:
To name the compound given above, do the following:
1. Locate the longest continuous carbon chain. This gives the parent name of the compound. In this case, the longest continuous carbon chain is 7. Thus the parent name is Heptane.
2. Identify the substituent group attached to the compound. In this case, the substituent group attached are:
a. Methyl (–CH₃). There are two methyl group attached.
b. Ethyl (–CH₂CH₃)
3. Locate the position of the substituent group attached to the compound by naming alphabetically.
a. The two Methyl (–CH₃) groups are located at carbon 2 and 3
b. The Ethyl (–CH₂CH₃) is located at carbon 4.
NOTE: The position of the Ethyl (–CH₂CH₃) group is the same from both side so we consider the lowest count for the methyl group.
4. Combine the above to obtain the name of the compound.
The name of the compound is:
4–ethyl–2,3–dimethylheptane
Answer:
If there reacted 1.5 moles of O2, there will be produced 1.0 mol of Fe2O3
Explanation:
Step 1: Data given
Number of moles oxygen reacted = 1.5 moles
Step 2: The balanced equation
4Fe + 3O2 → 2Fe2O3
Step 3: Calculate moles of Fe2O3
For 4 moles Fe consumed, we need 3 moles of O2 to produce 2 moles of Fe2O3
For 1.5 moles O2 consumed, we'll have 2/3 * 1.5 = 1.0 mol of Fe2O3
If there reacted 1.5 moles of O2, there will be produced 1.0 mol of Fe2O3
