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ollegr [7]
3 years ago
15

How many moles are in 55 g or NaCk

Chemistry
1 answer:
seraphim [82]3 years ago
4 0

Answer:

Explanation:

Ok, so I suppose you meant NaCl. But ok:

So we have the formula moles = grams/MM, where MM is molar mass. The molar mass of NaCl is 58.44 g/mol. That means that 55/58.44 is the number of moles which appears to be 0.94 moles.

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On a periodic table, the columns of elements with similar properties are:.
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Answer:

On a periodic table, the columns of elements with similar properties are called groups

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The total thermal energy of a system depends jointly on the temperature, total number of in the system _______________, and the
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Answer:

Molecules/State

Explanation:

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The total thermal energy refers to the total kinetic energies of these particles. It depends on the temperature of the system, the energies of the molecules present in the material and the arrangement of the object's molecules (states of matter).

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Use Lewis diagrams to show how electrons are shared to form covalent bonds in compounds wit the following atoms. Write the formu
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The Lewis structure/diagram for CH2O (aka Formaldehyde) can be written in either of the following ways shown in the picture.
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8 0
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In a chemical reaction how does the mass of the products compare with the mass of the reaction a greater thenb less thenc equal
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5 0
3 years ago
An unknown gas Q requires 2.67 times as long to effuse under the same conditions as the same amount of nitrogen gas. What is the
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Answer:

The correct answer is 199.66 grams per mole.

Explanation:

Based on law of effusion given by Graham, a gas rate of effusion is contrariwise proportionate to the square root of molecular mass, that is, rate of effusion of gas is inversely proportional to the square root of mass. Therefore,  

R1/R2 = √ M2/√ M1

Here rate is the rate of effusion of the gas expressed in terms of number of mole per uni time or volume, and M is the molecular mass of the gas.  

Rate Q/Rate N2 = √M of N2/ √M of Q

The molecular mass of N2 or nitrogen gas is 28 grams per mole and M of Q is molecular mass of Q and based on the question Q needs 2.67 times more to effuse in comparison to nitrogen gas, therefore, rate of Q = rate of N2/2.67

Now putting the values we get,  

rate of N2/2.67/rate of N2 = √28/ √M of Q

√M of Q = √ 28 × 2.67

M of Q = (√ 28 × 2.67)²

M of Q = 199.66 grams per mole

3 0
3 years ago
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