Using the formula A = l times w, solve the following word problem.

There are 950 students at Hanover High School. The ratio of the number of freshmen to all students is 3:10. The ratio of the num

-Dominant- [34]

Hi there! Since the ratios of students at Hanover High School are in different scales, we need to scale them up! First, let's take the ratio 1:2. This can be scaled up to 5:10. Now, combine the two ratios to find the ratio of freshmen to sophomores. 3:10 + 5:10 = 8:10. The remaining number is 2, since 8 + 2 = 10, so the ratio of freshmen to sophomores is 2:10!

Hope this was helpful!

7 0

3 years ago

How did they get the -5? I got -3

Naya [18.7K]

F(x) = x² - 3x
g(x) = √x - 1

f(g(x))= (√x - 1)² - 3(√x - 1) = (√x - 1)(√x - 1 - 3) =(√x - 1)(√x - 4) =
= √x √x -1*√x -4*√x +4 = x -5√x +4

Answer: x -5√x +4

4 0

2 years ago

What is 0.12 with 12 repeating as a fraction

strojnjashka [21]

12/99 is the fraction form

8 0

3 years ago

Read 2 more answers

for desert you can choose apple cherry blueberry or peach pie to eat and milk or juice to drink how many different possibilities

Liula [17]

Answer:

8 possibilities

Step-by-step explanation:

The pies we have to choose from are 1)Apple 2)Cherry 3)Blueberry or 4)Peach.

The beverages we have to choose from are 1)Milk and 2)Juice.

Here are the possibilities:

Apple + Juice

Apple + Milk

Cherry + Juice

Cherry + Milk

Blueberry + Juice

Blueberry + Milk

Peach + Juice

Peach + Milk

So we have a total of 8 possibilities for one pie and one beverage.

7 0

2 years ago

Astronomers treat the number of stars X in a given volume of space as Poisson random variable. The density of stars in the Milky

cupoosta [38]

Answer:

Explained below.

Step-by-step explanation:

The random variable X is defined as the number of stars in a given volume of space.

$X\sim \text{Poisson}\ (\lambda=1)$

The probability mass function of X is:

$p_{X}(x)=\frac{e^{-\lambda}\lambda^{x}}{x!}$

(7)

Compute the probability of exactly two stars in 16 cubic light-years as follows:

$P(X=2)=\frac{e^{-1}\times 1^{2}}{2!}=\frac{e^{-1}}{2}=\frac{0.36788}{2}=0.18394\approx 0.184$

(8)

Compute the probability of three or more stars in 16 cubic light-years as follows:

$P(X\geq 3)=1-P(X$

(9)

In 16 cubic light years there is only 1 star.

Then in 1 cubic light years there will be, (1/16) stars.

Then in 4 cubic light years there will be, 4 × (1/16) = (1/4) stars.

(10)

In 16 cubic light years there is only 1 star.

Then in 1 cubic light years there will be, (1/16) stars.

Then in t cubic light years there will be, [t × (1/16)] stars.

7 0

3 years ago