C. -5y -4 = -(x+3)^2 -1/2
Hope I am right.
Answer:
1.3 repeating
Step-by-step explanation:
The distance, s = 40t₁ where t₁ is the time to complete the outward journey.
The same distance = vt₂ where t₂ is the time to complete the return journey at speed v.
For the whole journey, 2s=60(t₁+t₂). Therefore s=30(t₁+t₂)=40t₁=vt₂.
30t₁+30t₂=40t₁, 10t₁=30t₂, t₁=3t₂, so s=120t₂=vt₂ and v=120kph.
The answer is
.
Let's solve your equation step-by-step.
2b+3b=3
Step 1: Simplify both sides of the equation.
2b+3b=3
(2b+3b)=3(Combine Like Terms)
5b=3
5b=3
Step 2: Divide both sides by 5.
5b/5=3/5
So, the answer is
.