Answer:
Keq = 2k₃
Explanation:
We can solve this exercise using Newton's second one
F = m a
Where F is the eleatic force of the spring F = - k x
Since we have two springs, they are parallel or they are stretched the same distance by the object and the response force Fe is the same for the spring age due to having the same displacement
F + F = m a
k₃ x + k₃ x = m a
a = 2k₃ x / m
To find the effective force constant, suppose we change this spring to what creates the cuddly displacement
Keq = 2k₃
Answer:
11.48 m
Explanation:
A brick starts from rest and gains a speed of 15 m/s and accelerates at 9.8 m/s^2
u = 0
v= 15
a= 9.8
s= ?
V^2 = U^2 + 2as
15^2 = 0^2 + 2 × 9.8×s
225= 19.6s
s= 225/19.6
s = 11.48m
Hence the brick will fall 11.48 m
