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3 years ago

How is motion converted to math

Physics

1 answer:

zvonat [6]3 years ago

7 0

Motion is never converted to math.

Math is only used to <em>DESCRIBE</em> motion. It can also describe a lot of other things. But it never gets converted to or from any of the things it describes.

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3 years ago

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3 years ago

Many battery-powered devices come with cords that allow them to be

lara [203]

Answer:

The change that has to take place inside the power cord in order for the device to function properly include;

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2 years ago

Enrico Fermi (1901–1954) was a famous physicist who liked to pose what are now known as Fermi problems, in which several assumpt

Katarina [22]

Answer:

Explanation:

(a)

Since the earth is assumed to be a sphere.

Volume of atmosphere = volume of (earth +atm osphere) — volume of earth

$= \frac{4}{3}\pi(6400+ 50)^3 - \frac{4}{3}\pi (6400)
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(b)

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$no.\, of\, molecules = 2.20\times 10^{20} moles \times \frac{6.022\times10^{23}\,molecules}{1mole}= 13.3\times10^{43} molecules
$

Hence the required molecules is $13.3\times10^{43} molecules
$

(c)

Write the ideal gas equation as follows:

$PV =nRT
\\\\n=\frac{1.0 atm \times 0.5L
}{0.08206 L\, atm/mol\,K \times (37 +273.1 5)K} = 0.0196 moles$

$no.\, of\, molecules = 0.0196 moles \times\frac{6.022\times10^{23} molecules}
{Imole}= 1.2\times 10^{23} molecules$

Hence the required molecules in Caesar breath is $1.2\times 10^{23} molecules$

(d)

Volume fraction in Caesar last breath is as follows:

$Fraction,\, X =\frac{12\times 10 molecules}{13.3\times 10^{43} \,molecules}= 9.0\times 10\, molecule/air\, molecule}$

(e)

Since the volume capacity of the human body is 500 mL.

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5 0

3 years ago

A golf ball strikes a hard, smooth floor at an angle of 28.2 ° and, as the drawing shows, rebounds at the same angle. The mass o

WITCHER [35]

Answer:

I = 1.06886 N s

Explanation:

The expression for momentum is

I = F t = Δp

therefore the momentum is a vector quantity, for which we define a reference system parallel to the floor

Let's find the components of the initial velocity

sin 28.2 = v_y / v

cos 28.2= vₓ / v

v_y = v sin 282

vₓ = v cos 28.2

v_y = 42.8 sin 28.2 = 20.225 m / s

vₓ = 42.8 cos 28.2 = 37.72 m / s

since the ball is heading to the ground, the vertical velocity is negative and the horizontal velocity is positive, it can also be calculated by making

θ = -28.2

v_y = -20.55 m / s

v_x = 37.72 m / s

X axis

Iₓ = Δpₓ = $p_{fx} - p_{ox}$

since the ball moves in the x-axis without changing the velocity, the change in moment must be zero

Δpₓ = m $v_{fx}$ - m v₀ₓ = 0

v_{fx} = v₀ₓ

therefore

Iₓ = 0

Y axis

I_y = Δp_y = p_{fy} -p_{oy}

when the ball reaches the floor its vertical speed is downwards and when it leaves the floor its speed has the same modulus but the direction is upwards

v_{fy} = - v_{oy}

Δp_y = 2 m v_{oy}

Δp_y = 2 0.0260 (20.55)

$\Delta p_{y}$ = 1.0686 N s

the total impulse is

I = Iₓ i ^ + I_y j ^

I = 1.06886 j^ N s

7 0

2 years ago