How many electrons can the first shell hold

A horizontal 953 N merry-go-round of radius 1.68 m is started from rest by a constant horizontal force of 73.9 N applied tangent

solniwko [45]

Answer:

K.E=365.2 J

Explanation:

Given data

Weight w =953 N

radius r=1.68 m

F=73.9 N

t=2.55 s

g=9.8 m/s²

To find

Kinetic Energy K.E

Solution

From the moment of inertia

$I=(1/2)MR^{2}\\ as \\W=mg\\So\\I=(1/2)(W/g)R^{2}\\I=(1/2)(953/9.8)(1.68)^{2}\\I=137.232kg.m^{2}$

The angular acceleration is given as

$a=T/I\\a=\frac{FR}{I}\\ a=\frac{(73.9)(1.68)}{137.232}\\a=0.905rad/s^{2}$

The angular velocity is given as

$w=at\\w=(0.905)(2.55)\\w=2.31rad/s$

So the Kinetic Energy is given as

$K.E=(1/2)Iw^{2}\\ K.E=(1/2)(137.232)(2.31)^{2}\\ K.E=365.2J$

3 0

3 years ago

What is the kinetic energy of a 1 kilogram ball is thrown into the air with an initial velocity of 30 m/sec

disa [49]

To find this we should use the equation Ek=1/2mv^2 where Ek is the kinetic energy, m is the mass and v is the velocity. So by this Ek=1/2*1*30^2 which then makes Ek=450 joules

5 0

3 years ago

Folding is usually the result of what type of stress

I am Lyosha [343]

<span>Compressional forces are the stress that would cause the effect called "Folding".</span>

8 0

3 years ago

Read 2 more answers

While working on her science fair project Venus connected a battery to a circuit that contained a light bulb. Venus decided to c

MakcuM [25]

When Venus put in a different battery with higher voltage ... no matter
what other components were in the circuit ... the voltage across the
light bulb, and the current through it, both had to increase, and the
light bulb had to shine brighter than before.

7 0

4 years ago

Read 2 more answers

A block of aluminum with a volume of 10 cm3 is placed in a beaker of water filled to the brim. Water overflows. The same is done

mihalych1998 [28]

Answer:

a) Both blocks displace the same amount of water.

Explanation:

Specific gravity (S.G.) is a quantity that tells how much and object is submerged on water and is given by:

$S.G=\frac{\rho_{block}}{\rho_{fluid}}$

with ρ the densities

Density of water is $997 \frac{kg}{m^{3}}$ and density of aluminum is $2712 \frac{kg}{m^{3}}$

So:

$S.G=\frac{2712}{997}=2.72$

A S.G. value bigger than one means the object is totally submerged so the water displaced is equal to the volume of the cube.

For the lead (density = $11340\frac{kg}{m^{3}}$ ) block we're going to calculate specific gravity in this case:

$S.G=\frac{11340}{997}=11.37$

Again S.G gravity is bigger than 1, so the lead block is totally submerged too, that implies the volume of water displaced is the volume of the block, that is the same volume as the aluminum block, so a is the correct one.

7 0

3 years ago