Answer:
Explanation:
First, we write the equations of motion for each axis. Since the crate is sliding with constant speed, its acceleration is zero. Then, we have:
Where T is the tension in the rope, F is the force exerted by the first worker, f_k is the frictional force, N is the normal force and mg is the weight of the crate.
Since 
and 
, we can rewrite the first equation as:
Now, we solve for 
and calculate it:
This means that the crate's coefficient of kinetic friction on the floor is 0.18.
Answer:
μ = 0.6
Explanation:
F = μN
N = mg
F = μmg
3 N = μ*0.5 kg * 9.8 m/s²
μ = 3/(0.5*9.8) = 0.6
Um I believe that it goes on top of the hoof
The area of the plates must have is(A)= 9.91×10⁷ m²
<h3 /><h3>How can we calculate the value of a area of a capacitor?</h3>
To calculate the the value of a area of the plates of a capacitor, we are using the formula,
C=
Or, A= 
Here we are given,
C= The desired capacitance of a capacitor.
= 0.23F
d=distance of separation between the plates.
=3.8mm= 0.0038m.
= permittivity of the vacuum.
=8.854×10⁻¹²F/m
We have to calculate the area of the plates must have = A m².
Now we put the known values in the above equation, we can get
A=
Or, A=
Or, A= 9.91×10⁷ m²
From the above calculation, we can conclude that the area of the plates must have is(A)= 9.91×10⁷m²
Learn more about Capacitor:
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The dimensional formula for the moment of force is [M1L2T−2].
