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2 years ago

7

How can gravitational tugs from orbiting planets affect the motion of a star?.

1 answer:

gayaneshka [121]2 years ago

3 0

Answer:

Gravitational tugs from orbiting planets don't affect the motion of a star. The star, being much larger than the planet, has a much smaller orbit. But it does move slightly. Explain how alien astronomers could deduce the existence of planets in our solar system by observing the Sun's motion.

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The distance between two charged objects is doubled. What happens to the electrostatic force between the two?a)It will double.b)

zzz [600]

Answer:

d) It will be cut to a fourth of the original force.

Explanation:

The magnitude of the electrostatic force between the charged objects is

$F=k\frac{q_1 q_2}{r^2}$

where

k is the Coulomb's constant

q1 and q2 are the charges of the two objects

r is the separation between the two objects

In this problem, the initial distance is doubled, so

r' = 2r

Therefore, the new electrostatic force will be

$F=k\frac{q_1 q_2}{(r')^2}=k\frac{q_1 q_2}{(2r)^2}=\frac{1}{4}(k\frac{q_1 q_2}{r^2})=\frac{1}{4}F$

So, the force will be cut to 1/4 of the original value.

5 0

3 years ago

What is the unit of pressure? Why is it called a derived unit?<br>Why has SI system

Dovator [93]

Answer:

pascal

Explanation:

its obtained after either division or multiplication

6 0

3 years ago

What is an example of situational irony in the excerpt?

Murrr4er [49]

Which excerpt are you talking about?

6 0

3 years ago

Read 2 more answers

A sound travels down a hallway that is 115 m long. Then it echoes and

yan [13]

Answer:

0.66 s

Explanation:

∆x = v∆t → 2 × 115 = 350 ∆t → ∆t = 230/350 = 0.66 s

7 0

2 years ago

A 125 g pendulum bob hung on a string of length 35 cm has the same period as when the bob is hung from a spring and caused to os

Bingel [31]

Answer:

k = 3.5 N/m

Explanation:

It is given that the time period the bob in pendulum is the same as its time period in spring mass system:

$Time\ Period\ of\ Pendulum = Time\ Period\ of\ Spring-Mass\ System\\2\pi \sqrt{\frac{l}{g}} = 2\pi \sqrt{\frac{m}{k}$

$\frac{l}{g} = \frac{m}{k}\\\\ k = g\frac{m}{l}$

where,

k = spring constant = ?

g = acceleration due to gravity = 9.81 m/s²

m = mass of bob = 125 g = 0.125 kg

l = length of pendulum = 35 cm = 0.35 m

Therefore,

$k = (9.81\ m/s^2)(\frac{0.125\ kg}{0.35\ m})\\\\$

<u>k = 3.5 N/m</u>

4 0

3 years ago