Answer:
480.40 g.
Explanation:
- According to the balanced equation:
<em>2 SO₂(g) + O₂(g) → 2 SO₃(g),</em>
it is clear that 2.0 moles of SO₂ react with 1.0 mole of oxygen to produce 2.0 moles of SO₃.
- We can get the no. of moles of SO₃ produced:
∵ 2.0 moles of SO₂ produce → 2.0 moles of SO₃, from the stichiometry.
∴ 6.0 moles of SO₂ produce → 6.0 moles of SO₃.
- Then, we can get the mass of the produced 6.0 moles of SO₃ using the relation:
<em>mass = no. of moles x molar mass of SO₃</em> = (6.0 moles)(80.066 g/mol) = <em>480.396 g ≅ 480.40 g.</em>
When the forward and reverse reaction rates are occuring at the same rate, the system is at equilibrium
Answer:
the fox population would increase
Explanation:
i think it would probably increase because there would be more food for the foxes to eat which would allow the foxes to grow in numbers
Answer:
K2 +Br ->2KBr
K + I ->KI
actually I don't know the e option but I had tried can u pls balance it urself
Answer:
the mass of CaO present at equilibrium is, 0.01652g
Explanation:
![K_p = [CO_2]](https://tex.z-dn.net/?f=K_p%20%3D%20%5BCO_2%5D)
= 3.8×10⁻²
Now we have to calculate the moles of CO₂
Using ideal gas equation,
PV =nRT
P = pressure of gas = 3.8×10⁻²
T = temperature of gas = 1000 K
V = volume of gas = 0.638 L
n = number of moles of gas = ?
R = gas constant = 0.0821 L.atm/mole.k
Now we have to calculate the mass of CaO
mass = 2.95 * 10 ⁻⁴ × 56
= 0.01652g
Therefore,
the mass of CaO present at equilibrium is, 0.01652g
