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3 years ago

How could you separate a mixture of acetone and alpha-naphthol?

Chemistry

1 answer:

puteri [66]3 years ago

8 0

Answer : The mixture of acetone and alpha naphthol can be separated using simple distillation method.

Explanation :

The melting point of alpha naphthol is around 95 °C whereas boiling point of acetone is around 55°C. Therefore the mixture can be separated using simple distillation method.

In this method, the mixture is taken in a stoppered bottle which has a tube inserted through the stopper for passing the vapors .The container is gently heated. Acetone being volatile, gets converted to vapors at its boiling point. Since melting point of alpha naphthol is much higher than the boiling point of acetone, it remains in dissolved form and does not melt when the mixture is heated.

The vapors of acetone are passed through the tube and as they pass through the tube, they get condensed. The condensed liquid is collected in another container.

After all the acetone is evaporated, solid alpha naphthol is left at the bottom of the container.

In this manner, the mixture of acetone and alpha naphthol is separated.

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3 years ago

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4 years ago

The average human body contains 5.60 L of blood with a Fe2 concentration of 3.00×10−5 M . If a person ingests 9.00 mL of 11.0 mM

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3 years ago

A sample of gaseous PCl₅ was introduced into an evacuated flask so that the pressure of pure PCl₅ would be 0.50 atm at 523 K. Ho

Lera25 [3.4K]

Answer:

Kp = 0.2215

Kc = 0.0052

Explanation:

Step 1: The balanced equation

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Step 2: given data

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The actual pressure in the flask was found to be 0.74 atm.

Step 3: Calculate the pressure after the decomposition

Pressure of PCl5 after decomposition = 0.5 - X

Since the equation has a ratio 1:1 the pressure after the decomposition of PCl3 and Cl2 is X

Step 4: Calculate total pressure at equilibrium

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Kp = P(PCl3)* P(Cl2) / P(PCl5)

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Step 6: Calculate Kc

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with P= the pressure of the gas in atm

with V= the volume of the gas in L

with n= the number of moles

with R= the gas constant in L*atm/mol*K

T = the temperature in Kelvin

P= nRT/V

Kp= Kc*(RT)^Δn

Kc=Kp/(RT)^Δn

Kc= 0.2215 / (0.08206*523)^1

Kc= 0.0052

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