Answer: D may be equal to, greater than, or less than the total amount of the reactants.
Explanation:
<em>mC: 12g/mol</em>
12g ------- 6,02·10²³ a.
6g --------- X
X = (6×<span>6,02·10²³)/12
</span><u>X = 3,01·10²³ atoms</u>
---->>> A :)
Answer:
1.07×10²¹ molecules are needed to sound the alarm
Explanation:
Let's convert the mass of CO to moles, to determine the amount of molecules.
0.05 g . 1 mol / 28 g = 1.78×10⁻³ moles
Now we can determine the number of molecules with the NA
1 mol has 6.02×10²³ molecules
1.78×10⁻³ moles may have (1.78×10⁻³ . 6.02×10²³) / 1 = 1.07×10²¹ molecules
Would be considered as an iconic bond.
500 mg in g :
1 g ----------- 1000 mg
? -------------- 500 mg
500 x 1 / 1000 => 0.5 g
total mass:
50 g + 0.5 g + 0.1 g => 50.6 g
hope this helps!
