Three of the four towns are on the vertices of the triangle ΔCBD, through
which the bearing can calculated.
<h3>Response:</h3>
- The bearing of D from B is approximately <u>209.05°</u>
<h3>Method by which the bearing is found;</h3>
From the given information, we have;
AC = AB = 25 km
∠BAC = 90° (definition of angle between north and east)
ΔABC = An isosceles right triangle (definition)
∠ACD = ∠ABC = 45° (base angles of an isosceles right triangle)
The bearing of <em>D</em> from <em>B</em> is the angle measured from the north of <em>B</em> to the
direction of <em>D.</em>
<em />
Therefore;
- The bearing of D from B ≈ 90° + (180° - 60.945°) = <u>209.05°</u>
Learn more about bearings in mathematics here:
brainly.com/question/10710413
3 in 350 is 300 the 3 in 403 is 3
Answer:
s = 6, r = 8 or s = 4, r = 7
Step-by-step explanation:
2r - s = 10
2r = 10 + s
r = 5 + s/2 --(1)
rs - s^2 = 12 --(2)
sub (1) into (2):
(5 + s/2)s - s^2 = 12
5s + 0.5s^2 - s^2 = 12
-0.5s^2 + 5s - 12 = 0
s^2 - 10s + 24 = 0
(s - 6)(s - 4) = 0
therefore s = 6 or s = 4
when s = 6, r = 8 and when s = 4, r = 7
if you would like to discover more about simultaneous equations, you can have a look at my Instagram page (learntionary). I'll be posting mathematics related stuff there and some of my notes (simultaneous enq notes are already posted!)
Answer: <u>30</u>
Step-by-step explanation:
Yvette- <em>100-7</em>
Isandro- <em>0+3</em>
1.) I'm going to speed up the process and multiply by 5.
Yvette: <em>100-7</em>
7 × 5 = 35
100-35= 65
65-35= 30
Isandro: <em>0+3 </em>
3 × 5 = 15
0+15= 15
15+15=<em> </em>30
2.) If they keep going on this pattern they will have the same number on the 10 round.
