Answer:
b.
Explanation:
In case of Single Slit, diffraction will occur.
Then In Single slit Diffraction, width of central fringe is
where D= distance b/w screen and slit
a= slit width
\lambda = wavelength
Thus if Screen width increases keeping other factors same then width of central fringe becomes narrower as
On increasing the slit width the central bright fringe width The width of the central bright fringe becomes narrower.
Answer:
(a) 19.71801m/s Velocity just before going up the ramp.
(b) 74.56338m.
Explanation:
We will solve it in two parts, first we will calculate time that 5kg wooden block would take to just reach ramp and with this time we will calculate final velocity that the wooden block would have in this time.
Second, we will calculate the component of velocity vector along inclined plane and the time that it would take for velocity to be 0 meters/s then with this time we will calculate the distance that inclined plane would travel along inclined plane.
Following formulas will be used.
(a) Calculating velocity right before going up the ramp.
Wooden block is going on a straightaway and has net for on it.
=
and this force produces acceleration of
With this acceleration, wooden block would reach at the foot of ramp in.
and final velocity will be
this velocity of wooden box just before going up the ramp.
(b) How far up the ramp will the wooden block go before stopping.
Ramp is at 20° relative to horizontal therefore velocity along the ramp that the wooden block would have will be.
and deceleration along the ramp is
Where force of friction along the inclined plane.
is a component of g along normal of the inclined plane.
And with this deceleration time needed to get wooded block to stop is.
and in that time wooden block would travel
This is how up wooden box will go before coming to stop.