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Ket [755]
2 years ago
9

QUESTION If the angular acceleration were doubled for the same duration, by what factor would the angular displacement change

Physics
1 answer:
astra-53 [7]2 years ago
7 0

Answer:

By a factor of 2

Explanation:

The angular displacement would change by a factor of 2.

The angular acceleration is represented by the formula

α = Δw / Δt, where

α = angular acceleration

Δw = change in velocity.

Δt = change in time taken

The angular displacement is given by the relation

s = rθ

s = arc length

r = distance

θ = angular displacement

We all know that velocity is the ratio of displacement and time, thus,

v = s/t

Angular acceleration on the other hand says that

α = w/t, substitute w for v, we have

α = s/t ÷ t

α = s/t * 1/t

α = s/t²

We see here that multiplying the acceleration by 2 will only be balanced by increasing the displacement by the same number, 2 in this case

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You're driving down the highway late one night at 21 m/s when a deer steps onto the road 35 m in front of you. Your reaction tim
andreev551 [17]

Speed with which initially car is moving is 21 m/s

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now the distance traveled by the car after applying bakes

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so total distance moved before it stop

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An ideal monatomic gas initially has a temperature of 300 K and a pressure of 5.79 atm. It is to expand from volume 420 cm3 to v
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b) The work done by the gas is 305.3 J.

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P_{f}: is the final pressure =?

V_{i}: is the initial volume = 420 cm³

V_{f}: is the final volume = 1450 cm³

n: is the number of moles of the gas

R: is the gas constant

P_{f} = \frac{P_{i}V_{i}}{V_{f}} = \frac{5.79 atm*420 cm^{3}}{1450 cm^{3}} = 1.68 atm

Hence, the final pressure is 1.68 atm.

b) The work done by the isothermal expansion is:

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Therefore, the work done by the gas is 305.3 J.

I hope it helps you!        

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